45 because 30 divided by 2 is 15 the 15 times 3
Answer:
Option B. minimum is correct for the first blank
Option C. 6 is correct for second blank.
Step-by-step explanation:
In order to find the maxima or minima of a function, we have to take the first derivative and then put it equal to zero to find the critical values.
Given function is:
Taking first derivative
Now the first derivative has to be put equal to zero to find the critical value
The function has only one critical value which is 5.
Taking 2nd derivative
As the value of 2nd derivative is positive for the critical value 5, this means that the function has a minimum value at x = 5
The value can be found out by putting x=5 in the function
Hence,
<u>The function y = x 2 - 10x + 31 has a minimum value of 6</u>
Hence,
Option B. minimum is correct for the first blank
Option C. 6 is correct for second blank.
Answer: 11/23
Step-by-step explanation:
I used my calculator to convert those fractions into decimal form and found the biggest number. It was about 0.4789.
Answer:
C
Step-by-step explanation:
It usually works best to use the polynomial with fewer terms as the multiplier. A row of partial products is written for each term of the multiplier, so the fewer terms will result in fewer rows of partial products.
In order to keep like terms together, it is preferable to allocate a separate column of the multiplication tableau to each power of the operands or product. This means we want to make note of the fact that the cubic multiplicand has a coefficient of 0 for its x^2 term.
The best setup is the one shown in the attachment.
Answer:
Case 1:
Case 2:
Case 3: Not possible
Step-by-step explanation:
Given
See attachment for illustration of each case
Required
Find AB and BC
Case 1:
Using Pythagoras theorem in ANB, we have:
This gives:
Take square roots of both sides
To calculate BC, we consider ANC, where:
Collect like terms
Take square roots
So:
Case 2:
Using Pythagoras theorem in ANB, we have:
This gives:
Collect like terms
Take square roots of both sides
To calculate BC, we consider ABC, where:
Collect like terms
Take square roots
Case 3:
This is not possible because in ANC
The hypotenuse AN (24) is less than AC (40)