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2 years ago

What is 202020 x 23 <<<<<<<

Mathematics

2 answers:

fredd [130]2 years ago

7 0

202020 x 23= 4646460

RoseWind [281]2 years ago

5 0

Answer:

202020 x 23 = 4646460

(I like the pictures! Btw, I am the first to answer. Brainliest pls! :D)

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Your class is learning how to tie knots.each student needs a peace of rope thatis 3/8 yards. how much do we need for 16 stdents

Lilit [14]

3/8 multiplied by 16
the answer is 6

8 0

2 years ago

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Help me with trigonometry

poizon [28]

Answer:

See below

Step-by-step explanation:

It has something to do with the Weierstrass substitution, where we have

$\int\, f(\sin(x), \cos(x))dx = \int\, \dfrac{2}{1+t^2}f\left(\dfrac{2t}{1+t^2}, \dfrac{1-t^2}{1+t^2} \right)dt$

First, consider the double angle formula for tangent:

$\tan(2x)= \dfrac{2\tan(x)}{1-\tan^2(x)}$

Therefore,

$\tan\left(2 \cdot\dfrac{x}{2}\right)= \dfrac{2\tan(x/2)}{1-\tan^2(x/2)} = \tan(x)=\dfrac{2t}{1-t^2}$

Once the double angle identity for sine is

$\sin(2x)= \dfrac{2\tan(x)}{1+\tan^2(x)}$

we know $\sin(x)=\dfrac{2t}{1+t^2}$ , but sure, we can derive this formula considering the double angle identity

$\sin(x)= 2\sin\left(\dfrac{x}{2}\right)\cos\left(\dfrac{x}{2}\right)$

Recall

$\sin \arctan t = \dfrac{t}{\sqrt{1 + t^2}} \text{ and } \cos \arctan t = \dfrac{1}{\sqrt{1 + t^2}}$

Thus,

$\sin(x)= 2 \left(\dfrac{t}{\sqrt{1 + t^2}}\right) \left(\dfrac{1}{\sqrt{1 + t^2}}\right) = \dfrac{2t}{1 + t^2}$

Similarly for cosine, consider the double angle identity

Thus,

$\cos(x)= \left(\dfrac{1}{\sqrt{1 + t^2}}\right)^2- \left(\dfrac{t}{\sqrt{1 + t^2}}\right)^2 = \dfrac{1}{t^2+1}-\dfrac{t^2}{t^2+1} =\dfrac{1-t^2}{1+t^2}$

Hence, we showed $\sin(x) \text { and } \cos(x)$

======================================================

$5\cos(x) =12\sin(x) +3, x \in [0, 2\pi ]$

Solving

$5\,\overbrace{\frac{1-t^2}{1+t^2}}^{\cos(x)} = 12\,\overbrace{\frac{2t}{1+t^2}}^{\sin(x)}+3$

$\implies \dfrac{5-5t^2}{1+t^2}= \dfrac{24t}{1+t^2}+3 \implies \dfrac{5-5t^2 -24t}{1+t^2}= 3$

$\implies 5-5t^2-24t=3\left(1+t^2\right) \implies -8t^2-24t+2=0$

$t = \dfrac{-(-24)\pm \sqrt{(-24)^2-4(-8)\cdot 2}}{2(-8)} = \dfrac{24\pm 8\sqrt{10}}{-16} = \dfrac{3\pm \sqrt{10}}{-2}$

$t=-\dfrac{3+\sqrt{10}}{2}\\t=\dfrac{\sqrt{10}-3}{2}$

Just note that

$\tan\left(\dfrac{x}{2}\right) = \dfrac{3\pm 8\sqrt{10}}{-2}$

and $\tan\left(\dfrac{x}{2}\right)$ is not defined for $x=k\pi , k\in\mathbb{Z}$

6 0

2 years ago

Ms. Skeen bought 3 pounds of candy for the Christmas party. There was a total of 147 pieces of candy. She wants to divide it amo

ohaa [14]

The 3 lbs of candy is irrelevant, so we can discard that. All you need to do is divide 147 by 26, which is 5.65 pieces of candy. Each student will get 5 pieces, with a few left over.

5 0

2 years ago

Graph the exponential function g(x)= 3/5^x

givi [52]

Hello!

You put the numbers in for x

3/5^-2 = 2.777
3/5^-1 = 1.667
3/5^0 = 1
3/5^1 = 0.6
3/5^2 = 0.36

The points are (-2, 2.777), (-1, 1.667), (0, 1), (1, 0.6), (2, 0.36)

Hope this helps!

3 0

3 years ago

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Aline's y-intercept is -6 and its slope is 0.What is its equation in slope-intercept form?

notka56 [123]

Answer:

y=0x+-6

Step-by-step explanation:

y=mx+b

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3 years ago