Given:
A space shuttle can travel at 28968 km/h.
To find:
The distance it can cover in 8 hrs.
Solution:
We have,
Speed of space shuttle = 28968 km/h.
So,
Distance covered by the space shuttle in 1 hour = 28968 km/h.
Distance covered by the space shuttle in 8 hour = (28968 × 8) km
= 231744 km
Therefore, the distance it can cover in 8 hrs is 231744 km.
Answer:
-27.51
Step-by-step explanation:
subtract the two numbers
Answer:
x = 15
Step-by-step explanation:
Pytago: a^2 + b^2 = c^2
x = 
= 15
Answer:
D
Step-by-step explanation:
Lengths:
WX: 2
XY: 2
WY: sqrt[(4-2)² + (2-4)²]
sqrt(4+4)
4sqrt(2)
W'(8, 16), X'(8, 8), Y'(16, 8)
W'X': 8 --> 4 × 2
X'Y': 8 --> 4 × 2
W'Y': sqrt[(16-8)² + (8-16)²]
sqrt(64 + 64)
8sqrt(2) --> 4 × 2sqrt(2)
D is a dilation with factor 4
