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2 years ago

Write an explicit formula for a(n) the n^th term of the sequence 216, 36, 6, ...

Mathematics

1 answer:

777dan777 [17]2 years ago

6 0

Answer:

Step-by-step explanation:

The explicit formula for the nth term is a%5Bn%5D=216%2A%281%2F6%29% where n starts at n=1. The 16th term is when n = 16, so.

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How do I do this problem ?

katrin2010 [14]

Y=13 Because a line equals 180. 180-11=169/13=13
x=8 because 180+22=202-4=198/11=18

3 0

2 years ago

Find the 37th term of 352,345,338

Mariulka [41]

Answer:

$a_{37}=100$

Step-by-step explanation:

Given that,

A sequence 352,345,338.

First term = 352

Common difference = 345-352 = -7

We need to find the 37th term of the sequence.

The nth term of an AP is given by :

$a_n=a+(n-1)d\\\\a_{37}=352+36\times (-7)\\\\a_{37}=100$

So, the 37th term of the sequence is 100.

8 0

2 years ago

The expression on the left side of an equation is shown below. If the equation has an infinite number of solutions, which expres

chubhunter [2.5K]

The answer is D. -2x+5.

If we simplify the left side of the equation first given, we come to the expression -2x-10.

If we solve for D., we get the same results. Thus, because an equation with all the same variable terms and constants have infinite solutions, the answer is D.

Hope this helps!

5 0

2 years ago

Read 2 more answers

Element X decays radioactively with a half-life of eight minutes. If there are 800 g of element X, how long, to the nearest 10th

Harman [31]

Answer: 41.5 min

Step-by-step explanation:

This problem can be solved with the Radioactive Half Life Formula:

$A=A_{o}.2^{\frac{-t}{h}}$ (1)

Where:

$A=22 g$ is the final amount of the radioactive element

$A_{o}=800 g$ is the initial amount of the radioactive element

$t$ is the time elapsed

$h=8 min$ is the half life of the radioactive element

So, we need to substitute the given values and find $t$ from (1):

$22 g=(800 g) 2^{\frac{-t}{8 min}}$ (2)

$\frac{22 g}{800 g}=2^{\frac{-t}{8 min}}$ (3)

$\frac{11}{400}=2^{\frac{-t}{8 min}}$ (4)

Applying natural logarithm in both sides:

$ln(\frac{11}{400})=ln(2^{\frac{-t}{8 min}})$ (5)

$-3.593=-\frac{t}{8 min}ln(2)$ (6)

Clearing $t$ :

$t=41.46 min \approx 41.5 min$ This is the time elapsed

7 0

2 years ago

Given f(x)=-x-5, solve for x when f(x)=-6

Deffense [45]

Answer:

f(x) = 1

Step-by-step explanation:

f(x) = -x-5

f(-6) = -(-6)-5 = 6-5 = 1

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2 years ago

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