So we have a 6 at the bottom, and the root is 3, so hmm how to take it out, simple enough, just let's get something to make the 6 a 6³, so it comes out of the root
so
Answer:
4) VW= 23
5) VW= 12
6) VW= 75
Step-by-step explanation:
4)
VU= 31
WU= 8
subtract 8 from 31
VW= 23
5)
UW= 18
UV= 6
subtract 6 from 18
VW= 12
6)
UV= 30
WU=45
add 30 and 45
VW= 75
M=0-5/1-0
m=-5/1=-5
y-y1=m*(x-x1)
y-5=-5(x-0)
y-5=-5x
y=-5x+5
Answer:
- c = -4.5
- z = 20
- x = -12
- a = -4/7
Step-by-step explanation:
A way to do this that will always work is ...
- eliminate parenthses and collect terms
- subtract any constants from the left side
- subtract any variable terms from the right side
- divide by the coefficient of the variable
1.
- 8c -11 -6c = -2
- 2c -11 = -2
- 2c = 9
- c = 4.5
2.
- 3z +4 -2z -9 = 15
- z -5 = 15
- z = 20
3.
- 12 -4x +18 = 36 +4x +18 -6x
- 30 -4x = 54 -2x
- -4x = 24 -2x
- -2x = 24
- x = -12
4.
- 36a -9a -5 = 6a -17
- 27a -5 = 6a -17
- 27a = 6a -12
- 21a = -12
- a = -12/21 = -4/7
Let x represent the number of hamburgers sold, and (x - 55) represent the number of cheeseburgers sold.
Set up an equation:
hamburgers + cheeseburgers = total number of burgers
x + (x-55) = 445
solve for x:
2x - 55 = 445
2x = 445 + 55
2x = 500
x = 500÷2
x = 250
This means 250 hamburgers were sold on Tuesday.
Hope this helps!
-Jabba