2 years ago

If segment AB segment BC and m<3 =36, find m<4

Mathematics

1 answer:

shepuryov [24]2 years ago

5 0

What are the measures of line segments AB and BC?

You might be interested in

Find the length of the third side. If necessary, round to the nearest tenth.

Shtirlitz [24]

240 bc you need to mulitpy it and ye

5 0

2 years ago

Read 2 more answers

How many quarts are there in 12 gallons and 3 quarts? enter the number only. Do not include units

lidiya [134]

Answer:

Step-by-step explanation:

5 0

2 years ago

The top of a round table is 4 feet in diameter. The top splits to allow two extra boards to be inserted. The expansion boards ar

Nutka1998 [239]

The answer will be 6

8 0

3 years ago

9. Three minutes after a hot tub starts to fill, the tub contains 24

Marianna [84]

Answer:

8 gallons per minute

Step-by-step explanation:

24 gallons in 3 minutes

you divide 24 by 3 which is 8

40 gallons in 5 minutes

you divide 40 by 5 which is 8

the relationship is that in both the answer was 8 as in 8 gallons per minute

6 0

2 years ago

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

2 years ago