I need this for today someone can help me!!!

Mathematics

1 answer:

kirill [66]2 years ago

4 0

Use pythagorean theorem
a^2 + b^2 = c^2

2^2 + 5^2 = 29

c^2 = 29

The distance from the school to the basketball courts is C, so to get C on its own we need to square root 29, which gives us 5.385.....

We need to round this to the nearest mile, so Josh would need to walk 5 miles. Hope this helps!!

You might be interested in

If the leg of a triangle is 48 and the hypotenuse is 60 what is the length of the other leg

AURORKA [14]

Answer:

The length of the other would be 36.

Step-by-step explanation:

a² + b² = c²

b² = c² - a²

b² = 60² - 48²

b² = 3600 - 2304

b² = 1296

√b² = √1296

b = 36

4 0

2 years ago

I need help with my math

mrs_skeptik [129]

Answer:

A=28

B=18

C=18

D=28

E=28

F=18

G=10

H=5

Step-by-step explanation:

3 0

1 year ago

Two poles are connected by a wire that is also connected to the ground. The first pole is 18 ft tall and the second pole is 24 f

9966 [12]

Answer:

72 feet from the shorter pole

Step-by-step explanation:

The anchor point that minimizes the total wire length is one that divides the distance between the poles in the same proportion as the pole heights. That is, the two created triangles will be similar.

The shorter pole height as a fraction of the total pole height is ...

18/(18+24) = 3/7

so the anchor distance from the shorter pole as a fraction of the total distance between poles will be the same:

d/168 = 3/7

d = 168·(3/7) = 72

The wire should be anchored 72 feet from the 18 ft pole.

_____

<em>Comment on the problem</em>

This is equivalent to asking, "where do I place a mirror on the ground so I can see the top of the other pole by looking in the mirror from the top of one pole?" Such a question is answered by reflecting one pole across the plane of the ground and drawing a straight line from its image location to the top of the other pole. Where the line intersects the plane of the ground is where the mirror (or anchor point) should be placed. The "similar triangle" description above is essentially the same approach.

Alternatively, you can write an equation for the length (L) of the wire as a function of the location of the anchor point:

L = √(18²+x²) + √(24² +(168-x)²)

and then differentiate with respect to x and find the value that makes the derivative zero. That seems much more complicated and error-prone, but it gives the same answer.