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2 years ago

May someone please help me with this :)

Mathematics

1 answer:

adoni [48]2 years ago

4 0

Answer:

Step-by-step explanation:

6+8=14 14+10=24

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Please answer this in two minutes

Fudgin [204]

Answer:

R = 21.8° to the nearest tenth

Step-by-step explanation:

To find Angle R we use tan

tan ∅ = opposite / adjacent

From the question

The opposite is 2

The adjacent is 5

So we have

tan R = 2/5

R = tan-¹ 2/5

<h3>R = 21.8° to the nearest tenth</h3>

Hope this helps you

3 0

2 years ago

the probability of a chance event is close to 0. which statement about the event is true/ (A) the event is likely to occur (B) t

Snezhnost [94]

The probability is always between 0 and 1 inclusive. If the probability is 0, the event is definitely not going to occur, and if the probability is 1, the event will definitely occur.

Now, if the probability of a chance event is close to 0, then the event is unlikely to occur.

6 0

2 years ago

12.6÷−4.2= Please help meeeeeeeeeeee

Reptile [31]

Answer:

Step-by-step explanation:

12.6/4.2 = 3

8 0

2 years ago

Read 2 more answers

Jose decides to go to the local amusement park. He pays $12.50 for an admission ticket and $4.50 per ride. The total amount that

-BARSIC- [3]

Answer:

Your answer is B. 4.50r + 12.50 = 71.

4 0

2 years ago

A car tracked 640 miles at a certain speed. If the speed of had been 8 mph faster, the trip could have been made in 4 hours less

Ket [755]

Answer:

$\large \boxed{\text{32 mi/h}}$

Step-by-step explanation:

Distance = rate × time, or

d=rt, so

$t = \dfrac{d}{r}$

Let x = original speed.

Then x + 8 = faster speed

Let t₁ = time at original speed

And t₂ = time at faster speed

Then t₂ = t ₁ - 4

$\begin{array}{rcl}t_{2} & = & t_{1} - 4\\\dfrac{640}{x + 8 } & = & \dfrac{640}{x} - 4\\\\640& = & \dfrac{640(x + 8)}{x} - 4(x + 8)\\\\640x& = & 640(x + 8) - 4x(x + 8)\\640x& = & 640x + 5120 - 4x^{2} - 32x\\4x^{2} + 32x - 5120& = & 0\\x^{2} + 8x - 1280& = & 0\\x + 40 = 0 & \text{or} & x - 32 = 0\\x = -40 & \text{or} & \mathbf{x = 32}\\\end{array}\\\text{We reject the negative speed, so $\mathbf{x = 32}$}\\\text{The original speed was $\large \boxed{\textbf{32 mi/h}}$}$

Check:

$\begin{array}{rcl}\dfrac{640}{x + 8 } & = & \dfrac{640}{x} - 4\\\\\dfrac{640}{32 + 8} & = & \dfrac{640}{32 } - 4\\\\\dfrac{640}{40} & = & 20 - 4\\\\16 & = & 16\\\end{array}$

OK.

4 0

2 years ago