Answer:
8
Step-by-step explanation:
100 = x^2 + AC^2
17^2 = AC^2 + (21 - x)^2
289 = AC^2 + 21^2 + x^2 - 2*21*x
289 =<u> AC^2</u> + 441 +<u> x^2</u> - 42x
from 1st equation AC^2 + x^2 = 100
289 = 441 + 100 - 42x
289 = 541 - 42x
42x = 541 - 289 = 252
x = 252/42 = 6
so AC^2 = 100 - 6^2 = 100 - 36 = 64
AC = 8
(3x^5y)^2=
3^2=9
(x^5)^2=x^10
y^2=y^2
(3x^5y)^2=9x^10y^2
9x^10y^2(4x^3y^5)=
9*4=36
x^10*x^3=x^13
y^2*y^5=y^7
9x^19y^2(4x^3y^5)= 36x^13y^7
Final answer: 36x^13y^7
The fractions you're given can be simplified down, so you get (12 ÷ 3) 4 hours on Monday, (21 ÷ 3) 7 hours on Tuesday, and (22 ÷ 3) 7 1/3 hours on Wednesday. You can now add these up and get your answer as 18 1/3 hours, or 18.33.
I hope this helps!
The first step for each of these is adding or subtracting the coefficient to isolate your terms with variables. And then divide to isolate the variable itself.
Answer:
On Wednesday
Step-by-step explanation:
In this question, We have Alana practicing for three days. We now need to know in which of the days has she practiced closest to 2 hours. Hence, what we are to do here is simply find which of the practicing hours is nearest to 2hours.
The best thing to do here is to work with minutes. Hence whatsoever fraction we are having would be worked with based on minutes. Let’s do this!
On Monday, she practiced 11/4 hours. This means she practiced 11/4 * 60 minutes = 165 minutes
On Tuesday, practice was for 19/8 hours. This means she had practiced for 19/8 *60 = 142.5 minutes
Lastly, on Wednesday, her practice time was 2.6 hours and that is 2.6 * 60 = 156 minutes
Kindly note that 2 hours is same as 120 minutes. We just need to know which of these minutes is closest to 120 minutes. From what we have, 142.5 is the closest.
This means that her practice on Wednesday is the closest to two hours.
