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2 years ago

10

In a football league, 4 coaches are needed for every 38 players. If 84 players sign up for softball, how many coaches are needed

?

1 answer:

pickupchik [31]2 years ago

6 0

9

8.842 but the answer would have to be rounded because you can’t have .842 coaches... the answers 9!!!!

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A ball with a rebound percentage of 45% was dropped from a height of 215feet. What is the height of the ball after the 5th bounc

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2 years ago

Subtract 5a-6b+7c from 13a-4b+8c

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A horse farm is developing a new indoor arena in a rectangular buliding. They want the width of the building to be 3 wide feet a

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The area of the building in terms of y in its simplest form is 12(y + 2)

Step-by-step explanation:

Since the area of a rectangle is A = LW where L = length and W = width. From our question, the width of the rectangular building is 3 feet. So, W = 3 feet and its length is 4y + 8 feet. So, L = 4y + 8 feet.

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2 years ago

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2 years ago

Read 2 more answers

Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a

just olya [345]

Answer:

$P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)$

$=P(Z$

So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and $X \sim Bin(n=600, p =0.4)$

And we want this probability:

$P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.
[tex]np=600*0.4=240\geq 10$

$n(1-p)=600*(1-0.4)=360 \geq 10$

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

$E(X)=np=600*0.4=240$

$\sigma=\sqrt{np(1-p)}=\sqrt{600*0.4(1-0.4)}=12$

And then $X \sim N (\mu = 240, \sigma= 12)$

And we are interested on the following probability:

$P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)$

$=P(Z$

So then the correct answer would be:

B) .9996

6 0

2 years ago