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2 years ago

What is the repeating digit of 4/9

Mathematics

2 answers:

Sonja [21]2 years ago

8 0

Its 0.4 and the 4 repeats infinitely :)

Burka [1]2 years ago

6 0

13 and brown and green orange orange

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Evaluate |3 - 5 + 7|.<br><br> -5<br> 5<br> -15<br> 15

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Which scatterplot does NOT suggest a linear relationship between x and y?

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Mrs. Spring left half of her estate to her son Sam. She left half of the remaining half to her cousin Fred. She left half of the

FinnZ [79.3K]

The total amount of Mrs. Spring's estate is $200,000

<h3>What is a fraction?</h3>

A fraction is written in the form of a numerator and a denominator where the denominator is greater than the numerator.

Example: 1/2, 1/3 is a fraction.

We have,

Let the total estate = 100x

Share left with Sam = 50x

Remaining share = 50x

Now,

Share left with cousin Fred = 1/2 of 50x = 25x

Remaining share = 25x

Share left with nephew Bill = 1/2 x (25x) = 12.5x

Remaining share = 12.5x

Share left with the care of the cat Chester = 12.5x

12.5x = $25,000

Now,

12.5x = $25,000

Multiply with 100/12.5 on both sides.

100/12.5 x 12.5x = 100/12.5 x $25,000

100x = $200,000

Thus,

The total amount of Mrs. Spring's estate is $200,000

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brainly.com/question/24370499

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5 months ago

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2 years ago

Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2.

insens350 [35]

Answer:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

Step-by-step explanation:

Given

$p(x) = \frac{x^2-2x-3}{x+2}$ -- Missing from the question

Required

The behavior of the function around its vertical asymptote at $x = -2$

$p(x) = \frac{x^2-2x-3}{x+2}$

Expand the numerator

$p(x) = \frac{x^2 + x -3x - 3}{x+2}$

Factorize

$p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}$

Factor out x + 1

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

$x -> -2^{-}$ Say x = -3

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

$p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12$

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

$x->-2^{-}, p(x)->-\infty$

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: $x>-2$

Say x = -2.1

$p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1$

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

$x->-2^{+}, p(x)->-\infty$

So, the behavior is:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

6 0

2 years ago