Answer:
Having the inside dimensions (ID) and the outside dimensions (OD) will allow you to figure out the wall thickness on tubing. You would need to subtract the ID from the OD and then divide by two. This number is the wall thickness.
Explanation:
The statement 'establishing a high critical value in a statistical test is associated with more confidence' is TRUE.
<h3>What is statistical significance?</h3>
The statistical significance is a arbitrary value used to indicate that data collected can be used to confirm (or reject) my working hypothesis.
The most widely used value to measure the statistical significance is the p threshold.
In conclusion, the statement 'Establishing a high critical value when calculating the results of a statistical test means that a researcher will have more confidence in finding significance than when a lower critical value is established' is TRUE.
Learn more about statistical significance here:
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Answer:
-54.12 V
Explanation:
The work done by this force is equal to the difference between the final value and the initial value of the energy. Since the charge starts from the rest its initial kinetic energy is zero.
The change in electrostatic potential energy , of one point charge q is defined as the product of the charge and the potential difference.
Answer:
R.E.T.A.R.D.A.T.I.O.N
Explanation:
It won't let me spell it normal
Answer:
The required pressure is 6.4866 atm.
Explanation:
The given data : -
In the afternoon.
Initial pressure of tire ( p₁ ) = 7 atm = 7 * 101.325 Kpa = 709.275 Kpa
Initial temperature ( T₁ ) = 27°C = (27 + 273) K = 300 K
In the morning .
Final temperature ( T₂ ) = 5°C = ( 5 + 273 ) K = 278 K
Given that volume remains constant.
To find final pressure ( p₂ ).
Applying the ideal gas equation.
p * v = m * R * T
= 657.2615 Kpa = 6.486 atm