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2 years ago

If you throw an apple towards the sky why its going up in spite of gravitational pull?

Physics

2 answers:

Margarita [4]2 years ago

7 0

Answer:

This could happen because the net force may be acting on only one side.

Explanation:

AlexFokin [52]2 years ago

6 0

Answer:

Force

Explanation:

The Force You Put Behind Said Apple Is Greater Than That Of Gravitational Pull

Example : The More Power You Put behind a basketball the higher the basketball will go

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A horizontal 2.00\ m2.00 m long, 5.00\ kg5.00 kg uniform beam that lies along the east-west direction is acted on by two forces.

Sunny_sXe [5.5K]

Answer: $240\ rad/s^2$

Explanation:

Given

Length of beam $l=2\ m$

mass of beam $m=5\ kg$

Two forces of equal intensity acted in the opposite direction, therefore, they create a torque of magnitude

$\tau =F\times l=200\times 2=400\ N.m$

Also, the beam starts rotating about its center

So, the moment of inertia of the beam is

$I=\dfrac{ml^2}{12}=\dfrac{5\times 2^2}{12}\\\\I=\dfrac{5}{3}\ kg.m^2$

Torque is the product of moment of inertia and angular acceleration

$\Rightarrow \tau=I\alpha\\\\\Rightarrow 400=\dfrac{5}{3}\times \alpha\\\\\Rightarrow \alpha =240\ rad/s^2$

7 0

2 years ago

Non-native species that have rapidly increasing populations that spread

hjlf

Answer:

Invasive Species

Explanation:

Plz give brainliest

6 0

2 years ago

A playground merry-go-round has a mass of 120 kg and a radius of 1.80 m and it is rotating with an angular velocity of 0.600 rev

natulia [17]

Answer:

The final velocity $\omega_f = 0.4235 \frac{rev}{s}$

Explanation:

Given data

Mass of merry go round $M_m$ = 120 kg

Radius = 1.8 m

Initial angular velocity $\omega_i$ = 0.6 $\frac{rev}{sec}$

Mass of boy $M_{boy}$ = 25 kg

We know that the final velocity is given by

$\omega_f = \frac{\frac{1}{2}M_m \omega_i }{M_{boy} + \frac{1}{2} M_m }$

Put all the values in above formula we get

$\omega_f = \frac{\frac{1}{2}(120) 0.6}{25 + \frac{1}{2} (120) }$

$\omega_f = 0.4235 \frac{rev}{s}$

This is the final velocity.

3 0

2 years ago

Firdavs [7]

1). The forces inside the atom are always, totally, completely, electrostatic forces. Those are so awesomely stronger than the gravitational forces that the gravitational ones are totally ignored, and it doesn't change a thing.

Parts 2 and 3 of this question are here to show us how the forces compare.

Part-2). The electrostatic force between a proton and an electron.

The constant in the formula is 9x10^9, and the elementary charge is 1.602 x 10^-19 Coulomb ... same charge on both particles, but opposite signs.

I worked through it 3 times and got 0.000105 N every time. So the best choice is 'C', even though we disagree by a factor of ten times. You'll see in part-3 that it really doesn't make any difference.

Part-3). Gravitational force between a proton and an electron.

The constant in Newton's gravity formula is 6.67x10^-11 . You'll have to look up the masses of the proton and the electron.

I got 2.163 x 10^-55 N ... exactly choice-C. yay !

Now, after we've slaved over a hot calculator all night, the thing that really amazes us is not only that the electrostatic force is stronger than the gravitational force, but HOW MUCH stronger ... 10^51 TIMES stronger. That's a thousand trillion trillion trillion trillion times stronger !

That's why it has no effect on the measurements if we just forget all about the gravitational forces inside the atom.

4 0

2 years ago

Read 2 more answers

A doctor observe areas of pink scaly skin on patient

murzikaleks [220]

Answer:

0-0 what is rhat supposed to mean. i dont think anyone can answer that lol

6 0

1 year ago