All categories

2 years ago

What is the lens equation?

Physics

2 answers:

Sergeeva-Olga [200]2 years ago

8 0

Answer:

1/V + 1/U = 1/F

Explanation:

Lens equation is

1/V + 1/U = 1/F

F = focal length

V = distance of image from the lens

U = distance of object from the lens

Note –

a) Distance of real object & image is negative and positive in sign respectively

b) Height above the optic axis are positive while height below the optic axis will be taken as negative

Strike441 [17]2 years ago

7 0

The lens equation gives d relation between focal length, object distance n image distance.

1/f = 1/v + 1/u

seldon

You might be interested in

Volume of an block is 5 cm3. If the density of the block is 250 g/cm3, what is the mass of the block ?

9966 [12]

Answer:

1.25kg

Explanation:

Simply multiply volume and density together

4 0

2 years ago

24. An elevator is moving vertically up with an acceleration a. The force exerted on the floor by a passenger of mass m is

Wewaii [24]

Given :-

An elevator is moving vertically up with an acceleration a.

To Find :-

The force exerted on the floor by a passenger of mass m .

Solution :-

As the man is in a accelerated frame that is non inertial frame , we would have to think of a pseudo force .

The direction of this force is opposite to the direction of acceleration the frame and its magnitude is equal to the product of mass of the concerned body with the acceleration of the frame .

For the FBD refer to the attachment . From that ,

$\implies Weight_{apparent}= mg + ma$

Hence option d is correct choice .

I hope this helps .

3 0

1 year ago

A bike accelerates uniformly(from rest to a speed of 7 m/s over a distance of 40 m. Determine

marshall27 [118]

Answer:

$0.61 m/s^2$

Explanation:

The bike's acceleration can be found by using the following suvat equation:

$v^2-u^2=2as$

where

v is the final velocity of the bike

u is the initial velocity

a is the acceleration

s is the distance covered

For the bike in the problem,

u = 0

v = 7 m/s

d = 40 m

Solving the equation for a, we find the acceleration:

$a=\frac{v^2-u^2}{2s}=\frac{7^2-0}{2(40)}=0.61 m/s^2$

3 0

2 years ago

Describe how newtons third law is related to fluid pressure.

Hatshy [7]

Fish swimming forward in the water, the water gets pushed backward because the fish moving forward is forcing the water to move backward, the motion forward and backward are the same, they are opposite and equal.

3 0

2 years ago

An object is dropped from a bridge. A second object is thrown downwards 1.0 s later. They both reach the water 20 m below at the

Lerok [7]

Answer:

Explanation:
Kinematics equation for first Object:

but:
The initial velocity is zero

it reach the water at in instant, t1, y(t)=0:

Kinematics equation for the second Object:
The initial velocity is zero

but:

it reach the water at in instant, t2, y(t)=0. If the second object is thrown 1s later, t2=t1-1=1.02s

The velocity is negative, because the object is thrown downwards

7 0

2 years ago