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2 years ago

How deep is the event horizon

Physics

1 answer:

Basile [38]2 years ago

7 0

Explanation:

The supermassive black holes that the Event Horizon Telescope is observing are far larger; Sagittarius A*, at the center of the Milky Way, is about 4.3 million times the mass of our sun and has a diameter of about 7.9 million miles (12.7 million km), while M87 at the heart of the Virgo A galaxy is about 6 billion solar ..

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Select the statement that best describes gravity.

pav-90 [236]

Explanation:

Gravity is the force of attraction between two objects. It depends upon the mass of the objects and the distance between the objects. Mathematically, the force of gravity is given by :

$F=G\dfrac{m_1m_2}{d^2}$

Where

G is the universal gravitational constant

$m_1\ and\ m_2$ are masses

d is the distance between two masses

So, statement (2) describes gravity "Gravity is the force of attraction between two objects; it is dependent upon the mass of the objects and the distance between the objects".

6 0

2 years ago

How much force is need to accelerate a skier that is 66kg at a rate of 2 m/s2?

lubasha [3.4K]

Answer:

132 N

Explanation:

newton's second law states that force = mass * acceleration

F = ma

plug in 66 kg for mass and 2 m/s^2 for acceleration

F = 66 * 2

F = 132 N

8 0

2 years ago

An ancient club is found that contains 100 g of pure carbon and has an activity of 6.5 decays per second. Determine its age assu

never [62]

Answer:

The age of living tree is 11104 years.

Explanation:

Given that,

Mass of pure carbon = 100 g

Activity of this carbon is = 6.5 decays per second = 6.5 x60 decays/min =390 decays/m

We need to calculate the decay rate

$R=\dfrac{-dN}{dt}=\lambda N=\dfrac{0.693}{t_{\frac{1}{2}}}N$ ....(I)

Where, N = number of radio active atoms

$t_{\frac{1}{2}}$ =half life

We need to calculate the number of radio active atoms

For $N_{12_{c}}$

$N_{12_{c}}=\dfrac{N_{A}}{M}$

Where, $N_{A}$ =Avogadro number

$N_{12_{c}}=\dfrac{6.02\times10^{23}}{12}$

$N_{12_{c}}=5.02\times10^{22}\ nuclie/g$

For $N_{c_{14}}$

$N_{c_{14}}=1.30\times10^{-12}N_{12_{c}}$

$N_{c_{14}}=1.30\times10^{-12}\times5.02\times10^{22}$

$N_{c_{14}}=6.526\times10^{10}\ nuclei/g$

Put the value in the equation (I)

$R=\dfrac{0.693\times6.526\times10^{10}\times60}{5700\times3.16\times10^{7}}$

$R=15.0650\ decay/min g$

100 g carbon will decay with rate

$R=100\times15.0650=1507\ decay/min$

We need to calculate the total half lives

$(\dfrac{1}{2})^{n}=\dfrac{390}{1507}$

$2^n=\dfrac{1507}{390}$

$2^n=3.86$

$n ln 2=ln 3.86$

$n=\dfrac{ln 3.86}{ln 2}$

$n =1.948$

We need to calculate the age of living tree

Using formula of age

$t=n\times t_{\frac{1}{2}}$

$t=1.948\times5700$

$t=11103.6 =11104\ years$

Hence, The age of living tree is 11104 years.

5 0

3 years ago

Is what flows and carries energy in a circuit

xenn [34]

The correct answer to this Electric current.

7 0

2 years ago

As mentioned in this week’s notes on page 4, the electrons of an atom can occupy different energy shells within the atom (simila

Nostrana [21]

The assume that goes with the inquiry demonstrates the wavelenghts of the photons transmitted by Balmer arrangement change , from vitality levels (n) 3, 4, 5, and 6 to the vitality level (n) 2, in hydrogen particles.

These are the values shown in the figure

Transition wavelength of the photon emitted
nm

from n=3 to n=2 656<------ this is the value requested

from n=4 to n=2 486

from n=5 to n=2 434

from n=6 to n=2 410

The wavelength of a photon discharged from the n = 3 shell in hydrogen is the primary information of the table, i.e 656 nm.

Using the conversion factor from nm to m that results is :

656 nm * 1 m / (10^9 nm) = 656 * 10 ^ -9 m.
Hope this helps

7 0

2 years ago