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evablogger [386]

2 years ago

8

Latasha explores some passages in a cave. The elevations of the passages are all above - 10 meters. Let y be the elevation of a

passage in meters. Write an inequality that represents elevations above -10 meters.

2 answers:

mojhsa [17]2 years ago

3 0

Answer:

Is this pure maths cause I don't know what's going on here

Tatiana [17]2 years ago

3 0

Answer:

It is y>-10

Step-by-step explanation:

i did it and i got it right.

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During the financial crisis of 2008, the price of a barrel of Brent crude oil fell from a high of $140 per barrel to around $50

andriy [413]

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Suppose you toss a coin 100 times and get 85 heads and 15 tails. Based on these results, what is the probability that the next

jenyasd209 [6]

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2 years ago

Let f (x) = 3x − 1 and ε > 0. Find a δ > 0 such that 0 < ∣x − 5∣ < δ implies ∣f (x) − 14∣ < ε. (Find the largest

s344n2d4d5 [400]

Answer:

This proves that f is continous at x=5.

Step-by-step explanation:

Taking f(x) = 3x-1 and $\varepsilon>0$ , we want to find a $\delta$ such that $|f(x)-14|$

At first, we will assume that this delta exists and we will try to figure out its value.

Suppose that $|x-5|$ . Then

$|f(x)-14| = |3x-1-14| = |3x-15|=|3(x-5)| = 3|x-5|< 3\delta$ .

Then, if $|x-5|$ , then $|f(x)-14|$ . So, in this case, if $3\delta \leq \varepsilon$ we get that $|f(x)-14|$ . The maximum value of delta is $\frac{\varepsilon}{3}$ .

By definition, this procedure proves that $\lim_{x\to 5}f(x) = 14$ . Note that f(5)=14, so this proves that f is continous at x=5.

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2 years ago