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2 years ago

The measures of two sides of a triangle are 15 and 16. between what two numbers must the measure of the third side fall?

1 answer:

6 0

If it is a right triangle and you given me adjacent and opposite the formula is
${r}^{2} = {x}^{2} + {y}^{2}$
third side = 21.93

if its not right triangle you need the angle to solve

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Andrew has one book 2 3/7 inches thick and a second book that is 3.56 inches thick. If he stacks the books, about how tall will

Vlada [557]

3/7 = 0.42
2.42 + 3.56 = 5.98 = 6.00
6.00 inches tall

8 0

4 months ago

Read 2 more answers

A civil engineer is analyzing the compressive strength of concrete. Compressive strength is normally distributed with A random s

evablogger [386]

Complete Question

A civil engineer is analyzing the compressive strength of concrete. Compressive strength is normally distributed with $\sigma^2=1000$ . A random sample of 12 sample specimens has a mean compressive strength of $\=x=3207psi$ . Round your answers to 1 decimal place. (a) Calculate the 95% two-sided confidence interval on the true mean compressive strength of concrete.

Answer:

$CI=(3189.1,3224.9)$

Step-by-step explanation:

From the question we are told that:

Sample size $n=12$

Standard deviation $\sigma^2=1000psi^2\\\sigma=\sqrt{1000} \\\sigma=31.6$

Sample mean $\=x=3207$

Confidence level =95%

$\alpha=100-95\\\alpha=0.05$ significance level

From table \alpha 0.05

Gives

$Z_c=1.96$

Generally the equation for confidence interval is mathematically given by

$CI=(\=x-\frac{z_c*\sigma}{\sqrt{n} } ),\=X+\frac{Z_C*\sigma}{\sqrt{12} })$

$CI=(3207-\frac{1.96*31.6}{\sqrt{12} } ),3207+\frac{1.96*31.6}{\sqrt{12} })$

$CI=(3189.1,3224.9)$

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1 year ago

There are 10 water bottles in 20 packages and but how much packages will he end up with when he drinks 20 of them?

makvit [3.9K]

Answer:

Step-by-step explanation:

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2 years ago

Choose the product. 4p^3(p^2 +8p-3

melisa1 [442]

I think you left a bracket which is really important for rhe solution but,these are the possible solutions depending on the bracket.Sorry if I made any mistakes
4p^3(p^2 +8p-3)
=4p^5+32p^4 - 12p^3

(or)
4p^3(p^2) +8p-3
=4p^5+8p-3

5 0

2 years ago

Find a if the point (3,a) is on the line that passes through (-2,7) and (5,-3).

saw5 [17]

Your first step is to find the slope of the line. You can find that using the formula $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ . Plug the x- and y- values from the coordinate pairs into the formula.

 $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ Plug in the coordinates
 $\frac{-3 - 7}{5 - (-2)}$ Cancel out the double negative
 $\frac{-3 - 7}{5 + 2}$ Add and subtract
 $\frac{-10}{7}$

Next, you can use the same formula to find a by setting it against the slope you just found.

slope = $\frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ Plug in the values
$\frac{-10}{7}$ = $\frac{7 - a}{-2 - 3}$ Subtract
$\frac{-10}{7}$ = $\frac{7 - a}{-5}$ Multiply both sides by 7
-10 = $\frac{7(7 - a)}{-5}$ Use the Distributive Property
-10 = $\frac{49 -7a}{-5}$ Multiply both sides by -5
50 = 49 - 7a Subtract 49 from both sides
1 = -7a Divide both sides by -7
$-\frac{1}{7}$ = a Switch the sides to make it easier to read
a = $-\frac{1}{7}$

8 0

2 years ago