Nana has a water purifier that filters 1/3 of the contaminates each hour

A town has three roads that form an obtuse triangle. James wants to set up a refreshment stand so that the shortest distance fro

GarryVolchara [31]

He should set up the refreshment stand on the incenter of the obtuse triangle. The incenter of a triangle is described as the intersection between the angle bisectors of a triangle. The inradius are the line segments from the incenter of the triangle to each of the three sides of the triangle which are all equal. The inradius is depicted as the radius of an inscribed circle in the triangle. Therefore, the shortest equal distance from his stand to each road is C. on the incenter.

4 0

2 years ago

The measure of the largest angle of a triangle is three times the measure of the smallest triangle and 2 more than the third ang

Zigmanuir [339]

Answer:

90 degrees, 60 degrees and 30 degrees

Step-by-step explanation:

90/3 = 30

30 x 2 = 60

6 0

2 years ago

Write an inequality and use substitution to solve the following problem:

nekit [7.7K]

They already spent $2000, and they only had $5100

Subtract

5100 - 2000 = 3100

$3,050 is your answer, because it is the only one that is less than 3100

hope this helps

7 0

2 years ago

Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam

Vlad [161]

Answer

$P(A) = 0.30$

$P(B) = 0.77$

$P(A\ n\ B) = 0.22$

$P(A\ u\ B) = 0.85$

Explanation:

Given

See attachment for proper data presentation

$n = 100$ --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

Here:

$Yes = 22$ and $No = 8$

$n(A) = Yes + No$

$n(A) = 22 + 8$

$n(A) = 30$

P(A) is then calculated as:

$P(A) = \frac{n(A)}{Sample}$

$P(A) = \frac{30}{100}$

$P(A) = 0.30$

Solving (b): P(B)

We only consider data in the Yes column.

Here:

$(1) = 22$ $(2) = 25$ and $(3) = 30$

$n(B) = (1) + (2) + (3)$

$n(B) = 22 + 25 + 30$

$n(B) = 77$

P(B) is then calculated as:

$P(B) = \frac{n(B)}{Sample}$

$P(B) = \frac{77}{100}$

$P(B) = 0.77$

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

i.e. [Supplier 1][Yes]

This is represented as: n(A n B)

$n(A\ n\ B) = 22$

The probability is then calculated as:

$P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}$

$P(A\ n\ B) = \frac{22}{100}$

$P(A\ n\ B) = 0.22$

Solving (d): P(A u B)

This is calculated as:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$

This gives:

$P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}$

Take LCM

$P(A\ u\ B) = \frac{30+77-22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

$P(A\ u\ B) = 0.85$

7 0

2 years ago

A town recreation hall needs to build a ramp. The height of the ramp must be 2 ft. The ramp will start 6 ft. from the door. To t

pogonyaev

The ramp will form a triangle with height 2ft and base 6ft.

The length of the ramp will be the hypotenuse of this triangle.
length² = height² + base²
length = √(height² + base²)
length = √(2² + 6²)
length = √(4 + 36)
length = √40
length = 6.3ft

Therefore, the ramp will be 6.3ft long.

5 0

2 years ago