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2 years ago

Does anyone know how to solve this ?

Mathematics

1 answer:

crimeas [40]2 years ago

3 0

9514 1404 393

Answer:

see below

Step-by-step explanation:

Make use of the quadratic formula.

For equation ax² +bx +c = 0, the solutions are ...

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

Here, you have a=1, b=-1, c=1, so the solutions are ...

$x=\dfrac{-(-1)\pm\sqrt{(-1)^2-4(1)(1)}}{2(1)}=\dfrac{1\pm\sqrt{1-4}}{2}=\dfrac{1\pm i\sqrt{3}}{2}\\\\\boxed{x=\dfrac{1+i\sqrt{3}}{2}\text{ and }x=\dfrac{1-i\sqrt{3}}{2}}$

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Answer:

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Step-by-step explanation:

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we substitute the value of the radius $r=7cm$ , and we get:

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