its 90 measurement CBG (I think) is corresponding to measurement DAE
<span>-6x - 2 = 40
-6x = 42
x = -7
..................</span>
301
We could start by finding the lowest common multiple of 2, 3, 4, 5, and 6, which is 60. Then, we can consider the next few multiples: 120, 180, 240, 300...
However, because we need a remainder of 1 when our number is divided by each of these numbers (2,3,4,5,6), we want to go one above each of these multiples. So we're talking about 61, 121, 181, 241, 301... Those are the numbers that will satisfy the "remainder of 1" part of the question.
Now, we need to find out which one satisfies the other part of the question, which just requires dividing each of these numbers by 7 to see which is divisible by 7 (in other words, which one gives us a remainder of zero when we divide by 7).
301 does it. 301/7 = 43. So 301 is a multiple of 7 and therefore will yield no remainder when divided by 7.
Hope this all makes sense.
The volume of a cube is just the side length cubed...
V=s^3 in this case:
V=39^3=59319 ft^3
and in cubic yards it is:
59319 ft^3*(yd^3/27 ft^3)=2197 yd^3
