<span>F for Frank, A or Alice.
F(initial)=1.95 inches
A(initial)=1.50 inches
Frank's equation at .25 inches per year and t representing year variable.
F=1.95+.25t
Alice's equation at .40 inches per year and t representing year variable.
A=1.5+.40t
To figure out how old they will be when their beaks are the same lengths set the equations equal to eachother as the equations are length.
1.95+.25t=1.5+.40t
.45=.15t
t=3 years</span>
F(y) = y + y^2 - 3
f(-2) = -2 + (-2^2) - 3
f(-2) = -2 + 4 - 3
f(-2) = -1
f(-4) = -4 + (-4^2) - 3
f(-4) = -4 + 16 - 3
f(-4) = 9
f(0) = 0 + 0^2 - 3
f(0) = -3
f(2) = 2 + 2^2 - 3
f(2) = 2 + 4 - 3
f(2) = 3
f(4) = 4 + 4^2 - 3
f(4) = 4 + 16 - 3
f(4) = 17
Answer:
3 rings
Step-by-step explanation:
10 / 2 = 5 necklaces
(5/5) x 2 = 2 bracelets
10 - 5 - 2 = 3<u> rings</u>
2x+10 is less than or equal to 20
the domain is 0, 1, 2, 3, 4, 5.
Answer:
p=4-2x
Step-by-step explanation: