35⋅34 9/20 4/10 4/5 5/4

An unknown solid acid has a formula h2x. How could you determine the molar mass of the unknown acid for a titration with 0.455 m

Goshia [24]

Answer:

The answer is in the explanation.

Explanation:

A titration of H₂X with KOH produce:

H₂X + 2KOH → 2H₂O + K₂X

It is possible to obtain the moles of H₂X because the moles of KOH are the spent volume of the titration in liters × 0,455M. As for a complete titration of H₂X moles you need twice moles of KOH you know the moles of KOH obtained are half H₂X moles.

As you know the mass of the solid acid that you titrate and molar mass of acid is:

mass of acid / moles of acid. You can determine the molar mass of the unknown acid.

I hope it helps!

3 0

2 years ago

What is an ellipse please help)

Natali5045456 [20]

Normal oval shape traced by a point moving in a plane so that the sum of the distance from the other points is constant.

3 0

2 years ago

Read 2 more answers

In an aqueous solution of a certain acid the acid is 0.10% dissociated and the pH is 4.06. Calculate the acid dissociation const

Kruka [31]

Answer : The acid dissociation constant Ka of the acid is, $8.7\times 10^{-5}$

Explanation :

First we have to calculate the concentration of hydrogen ion.

$pH=-\log [H^+]$

Given: pH = 4.06

$4.06=-\log [H^+]$

$[H^+]=8.71\times 10^{-5}M$

The dissociation of acid reaction is:

$HA\rightarrow H^++A^-$

Initial conc. c 0 0

At eqm. c-cα cα cα

Given:

Degree of dissociation = α = 0.10 % = 0.001

$[H^+]=c\alpha$

$8.71\times 10^{-5}=c\times 0.001$

$c=0.0871M$

The expression of dissociation constant of acid is:

$K_a=\frac{[H^+][A^-]}{[HA]}$

$K_a=\frac{(c\times \alpha)\times (c\times \alpha)}{(c-c\alpha)}$

Now put all the given values in this expression, we get:

$K_a=\frac{(0.0871\times 0.001)\times (0.0871\times 0.001)}{(0.0871-0.0871\times 0.001)}$

$K_a=8.7\times 10^{-5}$

Thus, the acid dissociation constant Ka of the acid is, $8.7\times 10^{-5}$

7 0

2 years ago

What type of reaction is A + B + heat → C + D

Harlamova29_29 [7]

When you need heat to make reaction happen it is endothermic.
If heat was on the right side then type of reaction would be exothermic.

5 0

2 years ago

the density of aluminum is 2.70g/cm^3. a piece of aluminum foil has a volume of 54.0 cm^3. what is the mass of this piece of alu

Neporo4naja [7]

The mass of aluminium foil is calculated as follows
mass = density x volume
density = 2.70 g/cm^3
volume 54 cm^3
mass of aluminium foil is therefore = 2.70 g/cm^3 x 54 cm^3 =145.8 grams
cm^3 cancel out each other

6 0

2 years ago