All categories

2 years ago

HEY CAN ANYONE PLS ANSWER DIS MATH QUESTION!!!!

Mathematics

1 answer:

Bogdan [553]2 years ago

5 0

Answer:

Step-by-step explanation:

Since it’s asking for numbers between -1 and 8 the equation cannot contain a equal symbol therefore it must be D

You might be interested in

That’s a little hint up above. Any help is deeply appreciated. I only have a limited time right now. So please try your best to

dolphi86 [110]

We need to know more information

7 0

2 years ago

CAN SOME ONE HELP ME ITS URGENT

aniked [119]

As we can observe from given information,

UT = ST

2x + 5 = x + 12

2x - x = 12 - 5

x = 7

now, let's solve for y

RU = RS

y - 4 = x + 5

y - 4 = 7 + 5

y = 12 + 4

y = 16

hope it helped...

5 0

2 years ago

If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by

PIT_PIT [208]

Answer:

The family of possible values for $p$ are:

$(-\infty, -4) \,\cup \,(7, +\infty)$

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

$\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|}$ (1)

Where:

$\theta$ - Angle between vectors, in sexagesimal degrees.

$\|\vec a\|, \|\vec b \|$ - Norms of vectors $\vec {a}$ and $\vec{b}$

If $\theta$ is acute, then the cosine function is bounded between 0 a 1 and if we know that $\vec {a} = (p, 3, -7)$ and $\vec {b} = (p, -p, 4)$ , then the possible values for $p$ are:

Minimum ( $\cos \theta = 0$ )

$\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0$

Maximum ( $\cos \theta = 1$ )

$\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1$

With the help of a graphing tool we get the family of possible values for $p$ are:

$(-\infty, -4) \,\cup \,(7, +\infty)$

7 0

2 years ago

1 3/4 TIMES 1/2 = ??? <br> PLS HELP FR NOW!!

Orlov [11]

Just do 7/4 and cross multiply with 1/2

3 0

1 year ago

Read 2 more answers

Help me with this plz

OleMash [197]

The answer is number 1.

4 0

2 years ago

Read 2 more answers