9.8 is the middle number which is the median
Answer:
i. x^2 – 1
ii. x^3 – 1
iii. x^4 - 1
Step-by-step explanation:
Products are obtained by multipliyng each left term by each rigth term as follows:
i. (x- 1)(x+ 1) = (x^2 – x + x - 1) = x^2 – 1 (equal terms with opposite sign substracts and the result is 0)
ii. (x- 1)(x^2 + x + 1) = (x^3 – x^2 + x^2 – x + x – 1) = x^3 – 1
iii. (x- 1)(x³ + x² + x + 1) = (x^4 – x^3 + x^3 – x^2 + x^2 – x + x – 1) = x^4 - 1
The lengths of each of the segments connected by the given pairs of points are:
1. AB = 10 units
2. CD = 17 units
3. EF = 3 units
<h3>How to Find the Length of Segments Connected by Two Points?</h3>
To find the length of a segment connected by two coordinate points, the distance formula is applied, which is:
d = .
1. Find the length of segment AB:
A(5,-3)
B(-3,3)
AB = √[(−3−5)² + (3−(−3))²]
AB = √[(−8)² + (6)²]
AB = √100
AB = 10 units
2. Find the length of segment CD:
C(-2, -7)
D(6, 8)
CD = √[(6−(−2))² + (8−(−7))²]
CD = √(64 + 225)
CD = 17 units
3. Find the length of segment EF:
E(5,6)
F(5,3)
EF = √[(5−5)² + (3−6)²[
EF = √(0 + 9)
EF = √9
EF = 3 units
Learn more about lengths of segments on:
brainly.com/question/24778489
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Even # --------- if it ends with 0, # of ways = 6*5*4 = 120 if not, 3 ways for ending digit, 5 ways for 1st digit, 5*4 for middle digits = 300
so total ways = 420
odd # --------- 4 ways of ending digit, 5 ways for 1st digit, 5*4 for middle digits = 400 ways
< 4000: ---------- 3 ways for starting digit, 6*5*4 ways for remaining digits = 360 ways
> 3000 & < 4000 ------------------------ 1 way for starting digit , 6*5*4 for remaining digits = 120 ways
Just gonna take a guess in case no one answers.
F(x) = .0365(x)275,000 + 275,000
is you wanna find out the 8th term plug in 8 for x...
should be
357,500 on year 8