Answer:
y = .5x+30
Step-by-step explanation:
<em>hope this helps, good luck :)</em>
Answer:
16
Step-by-step explanation:
8 × 4 = 32
32 × 1/2 = 16
Hope this helps <3
Cost of Lightbulb = x
cost of switch is x-8
9x + 4(x-8) = 520.50
Use distributive property:
9x + 4x -32 = 520.50
Simplify:
13x -32 = 520.50
Add 32 to both sides:
13x = 552.50
Divide both sides by 13
X = 42.50
A lightbulb costs $42.50
A switch costs 42.50-8 = $34.50
Given:
2002 sold 1000 paperback books and 1500 hardback books for a total of 2,500 books.
2003 sold 15% more paperback books and 5% more hardback books.
1000 x 1.15 = 1,150 paperbacks
1500 x 1.05 = 1,575 hardbacks
1150 + 1575 = 2,725
2,725 - 2,500 = 225
225 / 2,500 = 0.09
0.09 x 100% = 9% choice C
Since the height of an equilateral triangle in terms of its side s is s√3/2, the height of the triangle is 6√3/2 = 3√3 and so the area is (1/2)(6)(3√3) = 9√3.
<span>If we draw a horizontal line a height of h from the base of the triangle, the region is split into two regions: the lower region consisting of a trapezoid of height h and the upper region consisting of a triangle of height 3√3 - h. </span>
<span>Since the upper triangle and the triangle itself are similar triangles, the base and height are proportional. If we let x denote the base of the length of the upper triangle, we have: </span>
<span>(S. of small triangle)/(S. of big triangle) = (Ht. of small triangle)/(Ht. of big triangle) </span>
<span>==> x/6 = (3√3 - h)/(3√3) </span>
<span>==> x = (6√3 - 2h)/√3 </span>
<span>Thus, the area of the upper triangle is: </span>
<span>A = (1/2)[(6√3 - 2h)/√3](3√3 - h) = [(6√3 - 2h)(3√3 - h)]/(2√3). </span>
<span>(Made a dumb mistake about the height here for some reason) </span>
<span>Since we require that the area of this triangle is to be half of the total area (9√3/2), we need to solve: </span>
<span>[(6√3 - 2h)(3√3 - h)]/(2√3) = 9√3/2 </span>
<span>==> (6√3 - 2h)(3√3 - h) = 27 </span>
<span>==> 54 - 6h√3 - 6h√3 + 2h^2 = 27 </span>
<span>==> 2h^2 - 12h√3 + 27 = 0. </span>
<span>Solving with the Quadratic Formula gives: </span>
<span>h = (6√3 + 3√6)/2 ≈ 8.87 units and h = (6√3 - 3√6)/2 ≈ 1.52 units. </span>
<span>Since h = (6√3 + 3√6)/2 would place the line outside of the triangle, we pick h = (6√3 - 3√6)/2. </span>
<span>Therefore, the line should be ==> (6√3 - 3√6)/2 units from the base. </span>
<span>I hope this helps! ^^ Brainliest Please?</span><span>
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