You use y=mx+b... idk if that helped or not :)
The best way to find your answer is to divide 193 by 400 to get .4825 and to make sure if it is the answer you take 400 and multiply .4825 and it will be 193 so .4825 = 48.25%
<h3><u>The length is equal to 25.</u></h3><h3><u>The width is equal to 15.</u></h3>
l = 2w - 5
2l + 2w = 80
We have a value for l, so we can plug it into the second equation to solve for w.
2(2w - 5) + 2w = 80
Distributive property.
4w - 10 + 2w = 80
Combine like terms.
6w - 10 = 80
Add 10 to both sides.
6w = 90
Divide both sides by 6.
w = 15
Now that we have a value for w, we can plug it into the original equation to solve for l.
l = 2(15) - 5
l = 30 - 5
l = 25
Answer:
4
Step-by-step explanation:
Class width is said to be the difference between the upper class limit and the lower class limit consecutive classes of a grouped data. To calculate class width, this formula can be used:
CW = UCL - LCL
Where,
CW= Class width
UCL= Upper class limit
LCL= Lower class limit
From the table above:
For class 1, CW = 64 - 60 = 4
For class 2, CW = 69 - 65 = 4
For class 3, CW = 74 - 70 = 4
For class 4, CW = 79 - 75 = 4
For class 5, CW = 84 - 80 = 4
Therefore, the class width of the grouped data = 4
1,0,10,7,13,2,9,15,0,3/ 10
=60/10
=6
