2 years ago

How many grams calcium sulfite are in a 3.87 mole sample?

Chemistry

1 answer:

Nata [24]2 years ago

7 0

Answer:did you get the answer

Explanation:

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66.0 atm

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We can calculate the osmotic pressure (π) using the following expression.

$\pi = i \times M \times R \times T$

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i: van 't Hoff index

M: molarity

R: ideal gas constant

T: absolute temperature

Step 1: Calculate i

Sodium sulfate completely dissociates according to the following equation.

Na₂SO₄ ⇒ 2 Na⁺ + SO₄²⁻

Since it produces 3 ions, i = 3.

Step 2: Calculate M

We can calculate the molarity of Na₂SO₄ using the following expression.

$M = \frac{mass\ of\ solute }{molar\ mass\ of\ solute\ \times liters\ of\ solution} = \frac{65.0g}{142.04g/mol \times 0.500L} =0.915M$

Step 3: Calculate T

We will use the following expression.

K = °C + 273.15

K = 20°C + 273.15 = 293 K

Step 4: Calculate π

$\pi = 3 \times 0.915M \times \frac{0.08206atm.L}{mol.K} \times 293K =66.0 atm$

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