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2 years ago

In an arithmetic sequence, a3=15 and a8=0. What is the value of a5?

Mathematics

1 answer:

Nina [5.8K]2 years ago

7 0

Answer:

a3=15 , n=3

a8=0, n=8

a5 = ?

an = a1+ (n-1)d

a3 = a1 + (3-1) d

a3=a1+2d

and a8 = a1 + (8-1 )d

a8= a1+ 7d

15 = a1 + 2 d-------1

0= a1 +7 d----------2

substacting eq 2 from eq 1

15= - 5d

- 5d = 15

divide by - 5

d = -3

putting the value of d in eq 1

15 = a1 + 7 (-3)

15 = a1 -21

adding 21 on both sides

a1-21+21= 15+21

a1 = 36

a5 = ?, n=5, d= -3, a1=36

a5 = 36 + (5-1) (-3)

= 36+(4)(-3)

= 36-12

= 24

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h less-than 2

Step-by-step explanation:

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h ---> the number of hours

y ---> the total charge in dollars

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The linear equation is slope intercept form is equal to

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m is the slope or unit rate of the linear equation

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we have

<em>Grayson</em>

The slope is equal to $m=\$35\ per\ hour$

The y-intercept is $b=\$35$

The total charge is equal to

$y=35h+35$ ----> equation A

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The slope is equal to $m=\$45\ per\ hour$

The y-intercept is $b=\$15$

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2 years ago

Read 2 more answers