Both figures always have four sides
Let
x-------------> first odd integer
x+2---------> second odd integer
x+4---------> third odd integer
we know that
(x)+(x+2)+(x+4)=201--------> 3x+6=201--------> 3x=195-------> x=65
the three <span>sides of triangle RIO are
</span>x=65 in
x+2-----> 65+2-----> 67 in
x+4----> 65+4------> 69 in
then
69²=4761----------> c²
(65²+67²)=8714--------> a²+b²
c² < (a²+b²)---------> the triangle RIO is not obtuse
Is acute angle triangle
<span>statements
1) </span><span>The triangle is obtuse--------> is false
</span>Is acute angle triangle
<span>
2) </span><span>The triangle is scalene-----> is correct
The three sides measures are diferent
3)</span><span>The smallest side measures 61 inches--------> is false
</span><span>The smallest side measures 65 in
</span><span>
4)</span><span>The largest side measures 69 inches-------> is correct
</span><span>
5) </span><span>If triangle RIO is dilated of 1/3, then the perimeter of the dilated triangle will be 3 units smaller
</span><span>If triangle RIO is dilated of 1/3, then news sides are
</span>65/3------> 21.67 in
67/3-------> 22.33 in
69/3------> 23 in
the new perimeter is=21.67+22.33+23------> 67 in
201-67=134 in
therefore
If triangle RIO is dilated of 1/3, then the perimeter of the dilated triangle will be 3 units smaller----------> is false
Because the perimeter of the dilated triangle will be 134 units smaller
Answer:
we dont have all the information and dont know the question
Answer:
It is not a function.
Step-by-step explanation:
{(3,5),(-2,1),(<u>4</u>,3),(-1,<u>4</u>)}
A function is a special type of relation. In a function, no two ordered pairs have the same first component.
This relation has two 4s.
Answer:
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Population = 95
Given that the standard deviation of the Population = 5
Let 'X' be the random variable in a normal distribution
Let X⁻ = 96.3
Given that the size 'n' = 84 monitors
<u><em>Step(ii):-</em></u>
<u><em>The Empirical rule</em></u>
Z = 2.383
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = P(Z≥2.383)
= 1- P( Z<2.383)
= 1-( 0.5 -+A(2.38))
= 0.5 - A(2.38)
= 0.5 -0.4913
= 0.0087
<u><em>Final answer:-</em></u>
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087