By applying Segment Addition Postulate, segment FH is equal to 24 units.
<h3>What is a point?</h3>
A point can be defined as a zero dimensional geometric object and it is generally represented by a dot.
<h3>What is a line segment?</h3>
A line segment can be defined as the part of a line in a geometric figure such as a triangle, circle, quadrilateral, etc., that is bounded by two (2) distinct points and it typically has a fixed length.
<u>Given the following data:</u>
Since point H lies on line segment FG, we would apply Segment Addition Postulate to determine segment FH as follows:
FG = HG + FH
37 = 13 + FH
FH = 37 - 13
FH = 24 units.
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Complete Question:
Given that line segment FG = 37 and segment HG = 13, find segment FH.
2 Answers: Choice B and Choice C
The rate of change is 2.
The rate of change is constant.
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Explanation:
The first point on the left is when x = 1.5 and it has a height of y = 1
The point (1.5, 1) is on the line.
So is the point (3,4) for similar reasoning.
Compute the slope between those points
m = (y2-y1)/(x2-x1)
m = (4-1)/(3-1.5)
m = 3/(1.5)
m = 2
The slope is 2, which is the same as saying the rate of change is 2. This only applies when x > 1 of which the interval 1.5 ≤ x ≤ 3 is a part of.
Since the slope stays at 2 on the interval 1.5 ≤ x ≤ 3, this means we consider the slope to be constant. If the curve bended at all on this interval, then it wouldn't be a constant slope.
Answer:
C=110
Step-by-step explanation:
Angle C and the angle labeled 110 are alternate interior angles if the lines are parallel. Alternate interior angles are equal
C=110
Answer:
6
Step-by-step explanation:
40% is equal to 40/100
He made 40% of 15 shots so you miltiply 15 by 40/100 which is equal to 6.
<span>The answer is 7. Seven is a prime number, which means that its multiples are 1 and itself (7): 7 = 1 * 7. To find out which one is a factor of 7, we should divide each of them by 7. 1/7 will be a decimal number and 7/7 = 1, which is a whole number. Thus, 7 will be a multiple of 7 and also a factor of 7.Hope this helps. Let me know if you need additional help!</span>
