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2 years ago

Help please I don’t know the answer and I’m like late soo

Mathematics

2 answers:

icang [17]2 years ago

8 0

It’s the first one!

34kurt2 years ago

7 0

Answer:

I just want my points back lol

Step-by-step explanation:

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In the Fibonacci Sequence, each term after the first two terms is the sum of the preceding two terms. If the first two terms are

Snezhnost [94]

If the first two terms are 1 and 1, then what is the tenth term?

Answer:

The 10th term will be 55

Explanation:

In the Fibonacci Sequence, we add the previous digits to get the next digit. So, here 1st term is 1.

First term= 1

Second term = 0+1= 1

Third term= 1+1=2

Fourth term= 1+2= 3

Fifth term= 2+3= 5

Sixth term= 3+5= 8

Seventh term= 5+8 = 13

Eighth term= 8+13= 21

Ninth term= 13+21= 34

Tenth term= 21+34 = 55

So, the 10th term is 55.

5 0

2 years ago

In the given figure AB parallel to CD then value of x is?

Sveta_85 [38]

Answer:

x = 45

Step-by-step explanation:

AB // CD,

∠AB0 + ∠COB = 180 {Co interior angles}

75 + ∠COB = 180

∠COB = 180 - 75 = 105

∠DOE =∠COB {Vertically opposite angles}

∠DOE = 105

In ΔDOE,

x + 30 + 105 = 180 {angle sum property of triangle}

x + 135 = 180

x = 180 - 135

x = 45

4 0

2 years ago

What is the interest rate? A=500(1.0325)^12

saul85 [17]

I think you need to multiply

7 0

2 years ago

Of the 180 days of school last year, Grace was absent 15 days. What percent of the day was she absent?

Gennadij [26K]

To find the answer you take the days of the school and divide it by days absent so it is 15 divided by 180 witch is the answer is rounded to 8%

5 0

2 years ago

Read 2 more answers

The waiting time for a bus at a certain bus stop has a uniform distribution over the interval from 0 to 25 minutes. (a) What is

trapecia [35]

Answer:

(a) The probability that a person has to wait less than 6 minutes for the bus is 0.24.

(b) The probability that a person has to wait between 10 and 20 minutes for the bus is 0.40.

Step-by-step explanation:

Let The random variable X be defined as the waiting time for a bus at a certain bus stop.

The random variable X follows a continuous Uniform distribution with parameters a = 0 and b = 25.

The probability density function of X is:

$f_{X}(x)=\left \{ {{\frac{1}{b-a};\ a$

(a)

Compute the probability that a person has to wait less than 6 minutes for the bus as follows:

$P(X$

$=\frac{1}{25}\times \int\limits^{6}_{0}{1}\, dx$

$=\frac{1}{25}\times [x]^{6}_{0}$

$=\frac{1}{25}\times [6-0]$

$=0.24$

Thus, the probability that a person has to wait less than 6 minutes for the bus is 0.24.

(b)

Compute the probability that a person has to wait between 10 and 20 minutes for the bus as follows:

$P10$

$=\frac{1}{25}\times \int\limits^{20}_{10}{1}\, dx$

$=\frac{1}{25}\times [x]^{20}_{10}$

$=\frac{1}{25}\times [20-10]$

$=0.40$

Thus, the probability that a person has to wait between 10 and 20 minutes for the bus is 0.40.

8 0

2 years ago