A car is traveling clockwise around a circular racetrack of radius 1440m. When the car is at the northernmost point of the circl
1 answer:
Answer:
East
Explanation:
In circular motion, the velocity of the object will always be tangential to the radius of the circle. In this case, since the car is at the northernmost point of the circular track, then it must be moving right or towards the east, no matter what the acceleration might be at that very moment or what the radius of the track is. If it's moving clockwise, then it moves right (towards the east).
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Answer:
(a) = 4.19 x
N, and its direction is towards
.
(b) It must be placed inside a hollow shell.
Explanation:
Let, = 165 kg,
= 465 kg,
= 60 kg, and the distance between
and
is 0.340 m.
(a) Since is placed midway between
and
, then its distance to both masses is 0.170 m.
From the Newton's law of universal gravitation,
F =
Where all variables have their usual meaning.
Then,
a. =
-
=
= 2.25 x N
=
= 6.44 x N
∴ = = 6.44 x
- 2.25 x
= 4.19 x N
The net force exerted by the two masses on the 60 kg object is 4.19 x N.
(ii) // = /
/ - /
/
= 6.44 x - 2.25 x
= 4.19 x N
(iii) The direction of the net force is to the right i.e towards .
(b) For the net force experienced by the 60 kg object to be zero, it must be placed inside a hollow shell.