Explain the various modes of dispersal of seeds and fruits.

1 answer:

4 0

There are five main modes of seed dispersal: gravity, wind, ballistic, water, and by animals. Some plants are serotinous and only disperse their seeds in response to an environmental stimulus. Dispersal involves the letting go or detachment of a diaspore from the main parent plant.

Fruits and seeds dispersal is the process whereby fruits and seeds are scattered from their origin. The various ways by which fruit and seed are dispersed are known as agents of seed and fruit dispersal.

Check this link out for more information
https://qknowbooks.gitbooks.io/fruits-and-seeds/content/fruits_and_seeds_dispersal.html

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answer the following question by entering the numeric value with appropriate units. if the length of one side of a square is 12.

Tasya [4]

Using the length given '12 m', because the shape of the object is a square all sides are congruent.
Basically 12+12+12+12=48 or 12 x 4= 48
The answer is 48 m

8 0

2 years ago

Describe the particle that is emitted during alpha decay. How do you think an atom changes when it undergoes alpha decay?

weqwewe [10]

Answer:

Helium nuclei is emitted during alpha decay.

Explanation:

Alpha radiations are emitted as a result of radioactive decay. The atom emit the alpha particles consist of two proton and two neutrons. Which is also called helium nuclei. When atom undergoes the alpha emission the original atom convert into the atom having mass number 4 less than and atomic number 2 less than the starting atom.

Properties of alpha radiation:

Alpha radiations can travel in a short distance.

These radiations can not penetrate into the skin or clothes.

These radiations can be harmful for the human if these are inhaled.

These radiations can be stopped by a piece of paper.

Example:

₉₂U²³⁸ → ₉₀Th²³⁴ + ₂He⁴ + energy

8 0

2 years ago

50 POINTS PLEASE HELP!

Aleks04 [339]

Answer: The molar mass of the gas is 9.878 g/mol.

Explanation:

According to Graham's law, the rate of diffusion is inversely proportional to square root of molar mass of gas.

$Rate = \frac{1}{\sqrt{M}}$

where,

M = molar mass of gas

As given gas diffuses 1/7 times faster than hydrogen gas. So, its molar mass is calculated as follows.

$\frac{R_{1}}{R_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}\\$

where,

$M_{1}$ = molar mass of hydrogen gas

$M_{2}$ = molar mass of another given gas

$R_{1}$ = rate of diffusion of hydrogen

$R_{2}$ = rate of diffusion of another given gas = $\frac{1}{7}R_{1}$

Substitute the values into above formula as follows.

$\frac{R_{1}}{R_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}\\\frac{R_{1}}{\frac{1}{7}R_{1}} = \sqrt{\frac{M_{2}}{2}}\\7 \times 1.414 = M_{2}\\M_{2} = 9.878 g/mol$