1) 343/32 or 10.71875 or 10 23/32
2)-8
3)7
Answer:
12 cm
Step-by-step explanation:
To calculate the length of a spring with a 2 kg load, compare the displacement of a 1 kg load and adjust accordingly.
When a 1 kg load is suspended from the spring, the spring which is 6 cm stretches to 9 cm. This is 3 cm longer due to the weight. If you attach a weight which is twice as much then the displacement will be twice as much. Instead of stretching an additional 3 cm, it will stretch 2*3 = 6 cm. Add this to the length of the spring and it stretches in total 6 + 6 = 12 cm.
Answer:
If y(x-y)^2=x, then int1/(x-3y)dx is equal to (A) 1/3log{(x-y)^2+1} (B) 1/4log{(x-y)^2-1} (C) 1/2log{(x-y)^2-1} (D) 1/6 log{(x^2-y^2-1}
Step-by-step explanation:
Answer:y=1/2
Step-by-step explanation:
12.
13.
16.
is already in simplest form.