Answer:
(3,-3)
Step-by-step explanation:
If a coordinate (x, y) is dilated by a factor k, the resulting coordinate will be (kx, ky)
Given the coordinate (1, -1), if dilated by a factor of 3, the resulting coordinate will be (3(1), 3(-1)) = (3, -3)
Hence the required coordinate will be (3,-3)
X/8 + 12 = 16
start by subtracting twelve from both sides
x/8 + 12 = 16
- 12 -12
You're left with x/8 = 4
Multiply both sides by 8
8× x/8 = 4 ×8
Your answer is x = 32
If you need to simplify, the answer is 2.
1 ? I checked on the calculator and it said 1
Answer:
Step-by-step explanation:
Angle pair 1 and 8
and
Angle pair 2 and 7
When roots of polynomials occur in radical form, they occur as two conjugates.
That is,
The conjugate of (a + √b) is (a - √b) and vice versa.
To show that the given conjugates come from a polynomial, we should create the polynomial from the given factors.
The first factor is x - (a + √b).
The second factor is x - (a - √b).
The polynomial is
f(x) = [x - (a + √b)]*[x - (a - √b)]
= x² - x(a - √b) - x(a + √b) + (a + √b)(a - √b)
= x² - 2ax + x√b - x√b + a² - b
= x² - 2ax + a² - b
This is a quadratic polynomial, as expected.
If you solve the quadratic equation x² - 2ax + a² - b = 0 with the quadratic formula, it should yield the pair of conjugate radical roots.
x = (1/2) [ 2a +/- √(4a² - 4(a² - b)]
= a +/- (1/2)*√(4b)
= a +/- √b
x = a + √b, or x = a - √b, as expected.
