Answer:
Width = 52cm
Step-by-step explanation:
Step one:
given data
Area= 3276 cm squared
lenght= 63cm
Required
The width
Step two:
We know that
Area= L*W
substitute
3276= 63*W
divide both sides by 63
W= 3276/63
W=52cm
Answer:
The entire population is measured in both cases, so the actual difference in means can be computed and a confidence interval should not be used.
Step-by-step explanation:
A student working on a report about mathematicians decides to find the 98% confidence interval for the difference in mean age at the time of math discovery for Greek mathematicians versus Egyptian mathematicians. The student finds the ages at the time of math discovery for members of both groups, which include all Greek and Egyptian mathematicians, and uses a calculator to determine the 98% confidence interval based on the t distribution, <u>the entire population is measured in both cases, so the actual difference in means can be computed and a confidence interval should not be used.</u> There is no as such explanation of this scenario, its just the answer mentioned above.
Answer: 2√10 - √30
explanation:
ok so they’re asking for the difference between the lengths of the sides of each cube. they have different SA’s (surface areas). all you gotta do is plug in the SA in the given equation to find the length of the side and THEN you subtract the answers and thats how you find the difference between the sides.
given:
s = √(SA/6)
SA1 = 240 m^2
SA2 = 180 m^2
S1 = √(240/6) = 2√10 or 6.32
S2 = √(180/6) = √30 or 5.47
s1 -s2 = 2√10 - √30
Answer:
0.66
Step-by-step explanation:
1.00 - 0.34 = 0.66
The probability of certainty is 100%=1
If Probability(p)=0.34
then
0.34+Probability=1
Probability(!p)=1−0.34=0.66
Answer:
Step-by-step explanation:
We are told the school sold raffle tickets, and each ticket has a digit either 1, 2, or 3. The school also sold 2 tickets with the number 000.
Therefore we have the following raffle tickets:
123
132
213
231
312
321
000
000
From the given information, we can deduce that the school sold 8 tickets and only one ticket can contain the number arrangement of 123, but 000 appeared twice.
Probability of 123 to be picked=
1/8 => 0.125
Probability of 000 to be picked=
2/8 => 0.25
Since the probability of 000 to be picked is greater than 123, a ticket number of 000 is more likely to be picked