4975000000000-1815=4974999998185
Radius is 3.5
diameter is 7
You need to find points where the line g(x) intercepts the quadratic function f(x) in one and only one point.
Then 3x^2 + 4x -2 = mx - 5
solve 3x^2 + 4x - mx -2 + 5 = 0
3x^2 + (4 - m)x + 3 = 0
In order to there be only one solution (one intersection point) the radicand of the quadratic formula must be 0 =>
b^2 - 4ac = (4 - m)^2 - 4(3)(3) = 0
(4 - m)^2 = 24
4 - m = +/- √(24)
m = 4 +/- √(24) = 4 +/- 2√(6)
Then m, the slope of the line, may be 4 + 2√6 and 4 - 2√6
Answer:
-2 m/s^2
Step-by-step explanation:
Just as you would calculate the velocity when a body moves from point A to point B in a time T, we are going to calculate the acceleration as the difference of the velocities (final - initial) and divide it by the time it took:
Velocity_final = 10 m/s
Velocity_initial = 20 m/s
Time = 5 s
acceleration = (Velocity_final - Velocity_inital)/Time
= (10 m/s - 20 m/s)/5 s
= (-10 m/s) / 5s
= -2 m/s^2
The acceleration in m/s^2 is -2
D because y=3x-2
Y+2=3x
Y+2/3=x