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2 years ago

PLEASE HELP (TIMED TEST) WILL GIVE EXTRA POINTS

Mathematics

2 answers:

Aleonysh [2.5K]2 years ago

8 0

1.) is a

2.) is b

I dont have enough time to explain

MrRa [10]2 years ago

6 0

Answer:

The answers are A And B.

Step-by-step explanation:

Hope you pass!

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The average speed of a car driving down freeway is 70mph with a standard deviation of 5mph. Thid speed is normally distributed.

ikadub [295]

Answer:

0.081,0.2621,0.645,0.919

Step-by-step explanation:

Let X be the average speed of a car driving down freeway

Given that X is normal with mean as 70mph with a standard deviation of 5mph.

To convert to Z score we do

$Z =\frac{x-70}{5}$

a) the probability that a randomly selected car is driving more than 77mph

$=P(X>77)\\=P(Z>1.4)\\=0.081$

b) probability that a randomly selected car is driving between 65 and 69 mph

= $P(-1$

c) the probability that a randonly selected car is driving between 67 and 77mph

= $P(-0.6$

d) the probability that a randomly selected car is driving less than 77mph

$=P(Z$

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2 years ago

What is 500 thousands

seropon [69]

500,000 is the anwser

5 0

2 years ago

A region is bounded by y=e−3x, the x-axis, the y-axis and the line x = 3. If the region is the base of a solid such that each cr

grigory [225]

Answer:

0.333 $\pi$ units³

Step-by-step explanation:

Think process:

The equation is given as y = $e^{-3x}$

Let, y = f (x)

Therefore, $f (x) = e^{-3x}$

We know that the limits are y-axis and x= 3

Y-axis: x= 0

then limits are given as x= 0 and x = 3

Integrating gives:

$\int\limits^3_0 {e^{-3x} } \, dx$ = $\frac{-1}{3}e^{-3x}$ + C

calculating from x= 0 to x = 3, we know volume is given by $\pi \int\limits^a_b {f(x)} \, dx$

= $\pi$ [ $\frac{-1}{3} e^{-9} - (\frac{-1}{3} e^{0})$ ]

= $\pi$ [0.000041136 + 1/3]

= 0.333 $\pi$ units³

8 0

2 years ago

Will mark Brainliest if someone can help me!!!!! (Idk if Prinicipal is right 2-5)

Talja [164]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$1500\\ r=rate\to r\%\to \frac{r}{100}\dotfill &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1,2,3,4,5 \end{cases}$

$\bf A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 1}\implies A=1500(1.04)^1\implies A\approx 1560\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 2}\implies A=1500(1.04)^2\implies A\approx 1622.4\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 3}\implies A=1500(1.04)^3\implies A\approx 1687.3\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 4}\implies A=1500(1.04)^4\implies A\approx 1754.79\\\\\\A=1500\left(1+\frac{0.04}{1}\right)^{1\cdot 5}\implies A=1500(1.04)^5\implies A\approx 1824.98$

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2 years ago

What is 75 equals 6 multiplied by w

guajiro [1.7K]

75=6w is the answer to that

6 0

2 years ago

Read 2 more answers