The two numbers are 30 and 11
<em><u>Solution:</u></em>
Given that we have to separate the number 41 into two parts
Let the second number be "x"
<em><u>Given that first number is eight more than twice the second number</u></em>
first number = eight more than twice the second number
first number = 8 + twice the "x"
first number = 8 + 2x
So we can say first number added with second number ends up in 41
first number + second number = 41
8 + 2x + x = 41
8 + 3x = 41
3x = 41 - 8
3x = 33
x = 11
first number = 8 + 2x = 8 + 2(11) = 8 + 22 = 30
Thus the two numbers are 30 and 11
Get them to have a common denominator so you can add them
(1/3)×2= 2/6 and (1/2)×3= 3/6
Add them together
(2/6)+ (3/6)= 5/6
So 5/6 of the class planted either marigolds or tulips and 1/6 of the class planted neither
Let's solve ~
I hope you understood the procedure, please let me know if you have any doubts
Answer: A) y = 7x
<u>Step-by-step explanation:</u>
In order to be a proportional relationship, the equation MUST pass through the origin (0, 0) and only contain two coordinates
A) 0 = 7(0) ---> 0 = 0 TRUE
B) 0 = 2 + 3(0) ---> 0 = 2 False
C) 0 = Vz(0) ---> Too many variables so False
D) 0 = 5 - 0 ---> 0 = 5 False
