Answer:
36 Ω
Explanation:
Since the 3 resistors are connected in parallel.
The combined resistance of the resistor is
1/Rc = 1/R + 1/R + 1/R ...................... Equation 1
Where Rc = combined resistance of the three resistor, R1 = Resistance of each of the resistor
Rc = R/3 ....................... Equation 2
The formula of power is given as
P = V²/Rc
Rc = V²/P ................ Equation 3
Where V = Voltage, R = Combined Resistance, P = power.
Given: V = 48 V, 192 W.
Substitute into equation 3
Rc = 48²/192
Rc = 12 Ω
From equation 2
Rc = R/3
R = 3Rc
Where Rc = 12 Ω
R = 3×12
R = 36 Ω
Hence the resistance on each resistor = 36 Ω
<span>Answer:
Well, let's start by finding the pressure due to the "extra" height of the mercury.
p = 1.36e4 kg/m³ · (0.105m - 0.05m) · 9.8m/s² = 7330 N/m² = 7330 Pa
The pressure at B is clearly p_b = p_atmos = p_gas + 7330 Pa
The pressure at A is p_a = p_gas = p_atmos - 7330 Pa
c) 1 atm = 101 325 Pa
Then p_gas = 101325 Pa - 7330 Pa = 93 995 Pa</span>
4) They have non-moving magnetic fields.
Momentum of an object is calculated by multiplying the mass by the velocity.
p = mv
where:
p = momentum
m = mass
v = velocity
Let's take your given into account and put it in the equation:
p = mv
30,000 kg.m/s = (400kg)v
Velocity is our unknown, so to get it all we need to do is transfer mass (m) to the other side of the equation and isolate the velocity (v). When we do this, we need to use the opposite operation (rules of transposition).
(30,000kg.m/s)/(400kg) = v
Cancel out the kg and you are left with m/s.
75m/s = v
The answer is then D. 75 m/s.
Now for your second question, as you can see in the formula, mass and velocity is directly proportional to momentum. That means that the higher the mass or the velocity, the higher the momentum.
So if the velocity increases, the momentum increases as well.