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s344n2d4d5 [400]

2 years ago

11

Can someone please help me on this??

1 answer:

denpristay [2]2 years ago

6 0

Do ((x^3 - 2x^2 + 12x - 6) - (4x^2 - 6x + 4))(x)
(x^3 - 6x^2 + 18x - 10)(x)
ANSWER: x^4 - 6x^3 + 18x^2 - 10x

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What is the value of x?

Amanda [17]

hello

so to find x, we need to use a rule.

the rule is: the exterior angle of a triangle is equal to the sum of the opposite interior angles.

so our exterior angle is xº, and the opposite interior angles are 53º and 45º.

we could set up a basic equation (although not completely necessary)

xº=53º+45º

xº=98º

hope this helps

have a nice day :)

3 0

2 years ago

Read 2 more answers

If a textbook has a mass of 2.2kg and weighs 19.6 newtons on Venus what is the strength of gravity on Venus?

Neporo4naja [7]

G=mg=>g=G/m=8,9m/s^2

7 0

2 years ago

It rained 12 days out of 30 days. Which

aliya0001 [1]

The answer to your question is 4:10

3 0

2 years ago

Directions: Find the indicated trigonometric ratio as a fraction in simplest form. 1. Sin L =

Rainbow [258]

Answer:

$\sin L = 0.60$

$tan\ N = 1.33$

$\cos L = 0.80$

$\sin N = 0.80$

Step-by-step explanation:

Given

See attachment

From the attachment, we have:

$MN = 6$

$LN = 10$

First, we need to calculate length LM,

Using Pythagoras theorem:

$LN^2 = MN^2 + LM^2$

$10^2 = 6^2 + LM^2$

$100 = 36 + LM^2$

Collect Like Terms

$LM^2 = 100 - 36$

$LM^2 = 64$

$LM = 8$

Solving (a): $\sin L$

$\sin L = \frac{Opposite}{Hypotenuse}$

$\sin L = \frac{MN}{LN}$

Substitute values for MN and LN

$\sin L = \frac{6}{10}$

$\sin L = 0.60$

Solving (b): $tan\ N$

$tan\ N = \frac{Opposite}{Adjacent}$

$tan\ N = \frac{LM}{MN}$

Substitute values for LM and MN

$tan\ N = \frac{8}{6}$

$tan\ N = 1.33$

Solving (c): $\cos L$

$\cos L = \frac{Adjacent}{Hypotenuse}$

$\cos L = \frac{LM}{LN}$

Substitute values for LN and LM

$\cos L = \frac{8}{10}$

$\cos L = 0.80$

Solving (d): $\sin N$

$\sin N = \frac{Opposite}{Hypotenuse}$

$\sin N = \frac{LM}{LN}$

Substitute values for LM and LN

$\sin N = \frac{8}{10}$

$\sin N = 0.80$

7 0

2 years ago

An art teacher had 2/3 gallon of paint to pour into containers if he poured 1/8

exis [7]

To find your answer do 2/3 divided by 1/8 = 5 1/3 containers.

6 0

2 years ago