Answer:
Step-by-step explanation:
(a+b)^2=a^(2)+2ab+b^(2)
(a-b)^2=a^(2)-2ab+b^(2)
13)
(x+2)^(2)-(x-1)^2
x^(2)+4x+4-(x^(2)-2x+1)
x^(2)+4x+4-x^(2)+2x-1
6x+3
15)
(x+5)^(2)-(x+1)^2
x^(2)+10x+25-(x^(2)+2x+1)
x^(2)+10x+25-x^(2)-2x-1
8x+24
Answer:
159 m
Step-by-step explanation:
From the information given:
It was stated that if the ostrich ran towards the east direction in 7.95 s, let say the distance from the starting point is O towards the east side E, let called the distance towards the east side to be OE.
Again, the ostrich then runs in the south direction for 161 m, let the distance be OS.
Also, let the magnitude of the resultant displacement between the east direction to the south direction be ES = 226m.
We are to find, the magnitude of the ostrich's eastward component.
i.e. The distance traveled from the center to the east direction within the time frame of 7.95 s.
Using the Pythagoras rule:
ES² = OE² + OS²
226² = OE² + 161²
226² - 161² = OE²
OE² = 226² - 161²
OE² = 51076 - 25921
OE² = 51076 - 25921
OE² = 25155
OE = 158.60 m
OE ≅ 159 m
Thus, the magnitude of the ostrich's towards the eastward component. = 159 m.
Answer:
Use a graphing calc or desmos to help guide you.
Step-by-step explanation:
Answer:
42=7(z-3)
We simplify the equation to the form, which is simple to understand
42=7(z-3)
Reorder the terms in parentheses
42=+(+7z-21)
Remove unnecessary parentheses
+42=+7z-21
We move all terms containing z to the left and all other terms to the right.
-7z=-21-42
We simplify left and right side of the equation.
-7z=-63
We divide both sides of the equation by -07 to get z.
z=9