Answer:
40
Step-by-step explanation:
Answer: is 1/14
Explanation:
Answer:
it must also have the root : - 6i
Step-by-step explanation:
If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.
This is because in order to render a polynomial with Real coefficients, the binomial factor (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:
where the imaginary unit has disappeared, making the expression real.
So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)
Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.
<span>Given:
Net profit before tax = $208,000
Total equity = $500,000
Total assets = $330,000
Total liabilities = $150,000
Current assets = $64,000
Current liabilities= $45,000
Return on Equity = Net Income / Shareholder's equity = 208,000 / 500,000 = 0.416 or 41.6%.
Return on Assets = Net Income / Total Assets = 208,000 / 330,000 = 0.63 or 63%
Debt ratio = Total Liabilities / Total Assets = 150,000 / 330,000 = 0.4545 or 45.45%
Debt to equity ratio = Total liabilities / Total Equity = 150,000 / 500,000 = 0.30 or 30%
Current ratio = Current Assets / Current Liabilities = 64,000 / 45,000 = 1.42</span>