Answer: both of you have a lead yet but you can get it right away if I can see you guys again in a developer way but I have a game pass
Step-by-step explanation: yes
Answer:
We have
Stock = $200
Bonds = $100
Substitute these values into 1.08s+1.02b, where 's' is stock and 'b' is bond
.() + .() =
Predicted end of year value is $318
Answer:
ATLANTA — Hank Aaron, the man who broke Babe Ruth’s home run record and went on to hit 755 in his career, now wants to be remembered for something entirely different.
Step-by-step explanation:
Answer:
The equation does not have a real root in the interval ![\rm [0,1]](https://tex.z-dn.net/?f=%5Crm%20%5B0%2C1%5D)
Step-by-step explanation:
We can make use of the intermediate value theorem.
The theorem states that if 
is a continuous function whose domain is the interval [a, b], then it takes on any value between f(a) and f(b) at some point within the interval. There are two corollaries:
- If a continuous function has values of opposite sign inside an interval, then it has a root in that interval. This is also known as Bolzano's theorem.
- The image of a continuous function over an interval is itself an interval.
Of course, in our case, we will make use of the first one.
First, we need to proof that our function is continues in , which it is since every polynomial is a continuous function on the entire line of real numbers. Then, we can apply the first corollary to the interval , which means to evaluate the equation in 0 and 1:
Since both values have the same sign, positive in this case, we can say that by virtue of the first corollary of the intermediate value theorem the equation does not have a real root in the interval . I attached a plot of the equation in the interval ![\rm [-2,2]](https://tex.z-dn.net/?f=%5Crm%20%5B-2%2C2%5D)
where you can clearly observe how the graph does not cross the x-axis in the interval.
