Answer:
0.444 mol/L
Explanation:
First step is to find the number of moles of oxalic acid.
n(oxalic acid) =
Now use the molar ratio to find how many moles of NaOH would be required to neutralize of oxalic acid.
n(oxalic acid): n(potassium hydroxide)
1 : 2 (we get this from the balanced equation)
: x
x = 0.0111 mol
Now to calculate what concentration of KOH that would be in 25 mL of water:
A calcium atom has 20 protons!
There you go! I really hope this helped, if there’s anything just let me know! ☻
The answer is B. two chlorine atoms.
The chemical formula of the compound is BaCl2~
B.
And maybe put your question in the English/Literature tag next time lol
Answer:
high ph -basic,low pH -acidic
Explanation:
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