If a secant<span> and a </span><span>tangent of a circle </span><span>are drawn from a point outside the circle, then the product of the lengths of the secant and its external segment equals the square of the length of the tangent segment.
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y</span>² = 7(15+7)
<span>y</span>² = 7*22
<span>y</span>² = 154
<span>y = </span>√154
<span>y = 12.4 </span>← to the nearest tenth<span>
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Answer:
\[y = (-1/2) * x + 6\]
Step-by-step explanation:
Equation of the given line: y=2x+2
Hence the slope of the line is given by 2
Any line which is perpendicular to the given line will have a slope m such that m*2 = -1
Or, \[m = \frac{-1}{2}\]
Only options 2 and 3 satisfy this condition.
The line is also supposed to pass through the point (6,3).
Substituting these values in the option 2:
\[3 = (-1/2) * 6 + 3\]
Or, \[ 3 =0 \] which is false . Hence option 2 is not valid.
Now substituting (6,3) in option 3:
\[3 = (-1/2) * 6 + 6\]
Or, \[ 3 =3 \] which is true . Hence option 3 is the required equation of the line.
Answer: the cost of the car is $54600
Step-by-step explanation:
Let x represent the cost of the car.
She pays a deposit equal to 20% of the cost of the car. This means that the amount of money that she paid as deposit would be
20/100 × x = 0.2 × x = 0.2x
The remaining balance would be
x - 0.2x = 0.8x
She will pay the balance in 8 equal payments of $5460 each month. This means that
0.8x/8 = 5460
0.1x = 5460
Dividing the left hand side and the right hand side of the equation by 0.1, it becomes
0.1x/0.1 = 5460/0.1
x = 54600
9514 1404 393
Answer:
90° CCW
Step-by-step explanation:
The transformation from B to B' is ...
B(-4, 1) ⇒ B'(-1, -4)
(x, y) ⇒ (-y, x) . . . . . matches the transformation for 90° CCW