Answer:
<em>The answer is 13</em>
Step-by-step explanation:
Two positive and consecutive old numbers are x and x - 2.
=> x(x - 2) = 143
=> x^2 - 2x - 143 = 0
=> x^2 + 11x - 13x - 143 = 0
=> x(x + 11) - 13(x + 11) = 0
=> (x + 11)(x - 13) = 0
=> x = -11 (invalid)
or x = 13 (valid), the remaining number is 13 - 2 = 11
=> The two numbers are 11 and 13, and the greater number is 13.
Hope this helps!
:)
The Multiplication Property of Zero.
It states "the product of any number and zero is zero". Even if there are more than one multiplier - it is still 0.
So 5 x 0 = 0
100 x 0 = 0
41 x 0 x 3 = 0
etc.
<span>2x+3y=3
</span><span>-3x-2y=8
3y=3-2x
-2y = 8+3x
y = 1 - 2x/3
y = -4 - 3x/2
</span>1 - 2x/3 = -4 - 3x/2
5 = - 3x/2 + 2x/3
5 = -9x/6 + 4x/6
5 = -5x/6
x = 5 * 6/-5
x = -6
No plug it in.
<span>2x+3y=3 ; x = -6
-12 + 3y = 3
3y=3+12
3y=15
y = 5
So </span>x = -6 and y = 5
I'm not sure how to give you solid proof, like an equation or something, but you can see that out of the four coordinates, two of them have the y-value of 4 and two of them have the y-value of 2. Also, there is 1.5 in between each x-value that is paired with the same y-value... if that makes sense. So for (0.5, 2) and (3, 2), there is 1.5 in between 0.5 and 3. I hope this helps! Sorry it's a bit of a weird answer
Answer:
Hey there !
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