All categories

2 years ago

Computer monitors are measured by length of the screens what is the save of the tv is the sides ar 38 and 28.5

Mathematics

1 answer:

Damm [24]2 years ago

6 0

Sorry I do not know.

You might be interested in

Does anyone know the answers to these as well as the work shown for it?

a_sh-v [17]

Answer:

1=x4

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Suppose that fanf g are continuous functions,

shtirl [24]

The required result based on given continuous functions is: 207. See the explanation for same below.

<h3>What are continuous functions?</h3>

A continuous function in mathematics is one in which a continuous variation (that is, a change without a jump) of the argument causes a continuous variation of the function's value.

<h3>What is the calculation for the above solution?</h3>

Since G and F are continuous functions,

$\int_{12}^{28}) \, f(x) dx$ = 19

$\int_{12}^{28}) \, f(x) dx$ = 35

Therefore,

$\int_{12}^{28}) \, [K g(x) - 2 f(x)] dx$

= K $\int_{12}^{28}) \, g(x) dx -2 \int_{12}^{28}) \, f(x) dx$

So, given that K = 7, we have

7 x 35 - 2 x 19
= 245 - 38
= 207

Learn more about continuous functions at;
brainly.com/question/18102431
#SPJ1

7 0

1 year ago

Hey factory can produce fifth refrigerators in eight hours how many hours would it take to produce 1250 refrigerators

jarptica [38.1K]

Hey, I'm assuming you mean five refrigerators every eight hours. So . . .

1250 divide by 5. Which gives you 250.

Then take that 250 and multiply it by 8, and you have 2000.

So it would take 2000 hrs for a factory, that can produce 5 refrigerators every eight hours to, produce 1250 refrigerators.

6 0

2 years ago

Read 2 more answers

which of the following expresses the coordinates of the foci of the conic section shown below? (x-2)^2/4+(y+5)^2/9

elena55 [62]

Step-by-step explanation:

$\frac{(x - 2) {}^{2} }{4} + \frac{(y + 5) {}^{2} }{9} = 1$

This is the equation of the ellipse. Since the denominator is greater for the y values, we have a vertical ellipse. Remember a>b, so a

The formula for the foci of the vertical ellipse is

(h,k+c) and (h,k-c).

where c is

Our center (h,k) is (2, -5)

${c}^{2} = {a}^{2} - {b}^{2}$

Here a^2 is 9, b^2 is 4.

${c}^{2} = 9 - 4$

${c}^{2} = 5$

$c = \sqrt{5}$

So our foci is

$(2, - 5 + \sqrt{5} )$

and

$(2, - 5 - \sqrt{5} )$

6 0

1 year ago

Halla la tasa de variación de cada funcion en el intervalo [-4,3] e indica si es positiva , negativa o nula A) f(x)=x2-2x+4 B) f

masya89 [10]

Answer:

$A) \hspace{3}Rate\hspace{3}of\hspace{3}change=-5\hspace{3}Negative\\\\B)\hspace{3}Rate\hspace{3}of\hspace{3}change=-21\hspace{3}Negative$

Step-by-step explanation:

Given a function $f(x)$ , we called the rate of change to the number that represents the increase or decrease that the function experiences when increasing the independent variable from one value " $x_1$ " to another " $x_2$ ".

The rate of change of $f(x)$ between $x_1$ and $x_2$ can be calculated as follows:

$Rate\hspace{3}of\hspace{3}change=f(x_2)-f(x_1)$

For:

$f(x)=x^2-2x+4$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=(-4)^2-2(4)+4=16-8+4=12\\f(x_2)=f(3)=(3)^2-2(3)+4=9-6+4=7$

So:

$Rate\hspace{3}of\hspace{3}change =7-12=-5\hspace{3}Negative$

And for:

$f(x)-3x+2$

Let's find $f(x_1)$ and $f(x_2)$ , where:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

So:

$Rate\hspace{3}of\hspace{3}change =-7-14=-21\hspace{3}Negative$

<em>Translation:</em>

Dada una función $f(x)$ , llamábamos tasa de variación al número que representa el aumento o disminución que experimenta la función al aumentar la variable independiente de un valor " $x_1$ " a otro " $x_2$ ".

La tasa de variación de $f(x)$ entre $x_1$ y $x_2$ , puede ser calculada de la siguiente forma:

$Tasa\hspace{3}de\hspace{3}variacion=f(x_2)-f(x_1)$

Para:

$f(x)=x^2-2x+4$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion =7-12=-5\hspace{3}Negativa$

Y para:

$f(x)-3x+2$

Encontremos $f(x_1)$ y $f(x_2)$ , donde:

$[x_1,x_2]=[-4,3]$

$f(x_1)=f(-4)=-3(-4)+2=12+2=14\\f(x_2)=f(3)=-3(3)+2=-9+2=-7$

Entonces:

$Tasa\hspace{3}de\hspace{3}variacion=-7-14=-21\hspace{3}Negativa$

8 0

2 years ago