Answer:
Yes
Explanation:
the amino acids in proteins and the fatty acids in fat replace the amino and fatty acids in your brain to help you function and develop correctly.
Answer:
The value of the missing equilibrium constant ( of the first equation) is 1.72
Explanation:
First equation: 2A + B ↔ A2B Kc = TO BE DETERMINED
⇒ The equilibrium expression for this equation is written as: [A2B]/[A]²[B]
Second equation: A2B + B ↔ A2B2 Kc= 16.4
⇒ The equilibrium expression is written as: [A2B2]/[A2B][B]
Third equation: 2A + 2B ↔ A2B2 Kc = 28.2
⇒ The equilibrium expression is written as: [A2B2]/ [A]²[B]²
If we add the first to the second equation
2A + B + B ↔ A2B2 the equilibrium constant Kc will be X(16.4)
But the sum of these 2 equations, is the same as the third equation ( 2A + 2B ↔ A2B2) with Kc = 28.2
So this means: 28.2 = X(16.4)
or X = 28.2/16.4
X = 1.72
with X = Kc of the first equation
The value of the missing equilibrium constant ( of the first equation) is 1.72
The general properties of Group 1 alkali metals are:
1. They form cations.
2. They are highly reactive.
3. They have a charge of +1.
4. They form ionic compounds.
5. When their oxides or hydroxides are reacted in water, they form alkalis i.e. bases.
6. They are usually soft in nature.
7. They have low densities.
Explanation:
A cup of mixtures of iron fillings, sand and salt is a mixture who constituents are in the same phase i.e solid.
To separate them out we use the physical properties of the substances.
- First spread out the mixture uniformly over a piece of paper or on the table.
- Pass a bar magnet over it.
- The iron fillings will become attracted to the magnet and separate from the mixture.
- then pour water into the mixture of sand and salt
- the salt will dissolve since sand is made up of quartz which are highly insoluble.
- separate the water solution. Evaporate to dryness and recover the salt.
- the sand is left behind and dried.
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Answer:
12.62 L
Explanation:
First, we have to calculate the moles corresponding to 18.0 g of oxygen gas (MW 32.0).
18.0 g × (1 mol/32.0 g) = 0.563 mol
Then, we can find the volume occupied by 0.563 moles of oxygen at STP (273,15 K, 1.00 atm) using the ideal gas law.
P × V = n × R × T
V = n × R × T / P
V = 0.563 mol × 0.0821 atm.L/mol.K × 273.15 K / 1.00 atm
V = 12.62 L