Find the length of a to the nearest tenth using the Pythagorean theorem
1 answer:
Answer:
Ab^2 = CA^2 + BC^2
8^2 = 6^2 + a^2
64 = 36 + a^2
64-36 = a^2
28 = a^2
square root of 28 = square root of a^2
5 ,29 = a
5 = a
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Answer:
A 62°
B 118°
C 62°
D 118°
E 50°
F 58°
G 120°
H 120°
I 120°
J 60°
K 60°
L 60°
M 120°
N 120°
O
P 60°
Q 35.5°
R 49°
S 35.5°
T 109°
U 71°
V 109°
W 60°
